Cooler 1
Cooler 1
Cooler 1
Rear End
Head
Aliran outlet
Water in
t 2 t1
LMTD =
ln (t 2 / t1 )
113
= 411,82 oF
Ft =1 (Fig.18, Kern)
t = 411,82 oF
3. Temperatur Rata-rata
T1 T 2
Tavg =
2
= 518 oF
t1 t 2
tavg =
2
= 102,20 oF
4. Menentukan luas daerah perpindahan panas
Asumsi UD = 150 Btu/hr.ft2.oF (Tabel 8, Kern)
Q
A =
U D . t
= 51.166.952,47 ft2
150 411,82
= 828,31 ft2
Karena A > 200 ft2, maka digunakan Shell & Tube Heat Exchanger
5. Spesifikasi tube dan shell
Tube Side
Panjang tube (L) = 18 ft
Outside Diameter (OD) = 0,75 in
BWG = 18
Pass =1
a” = 0,1963 ft2/lin ft
Jumlah tube, Nt = A
828,31 ft2
Lx0,1963
= 18 a"
= 234,42
Dari tabel.9 Kern, didapat nilai yang mendekati Nt perhitungan adalah
Nt = 239
Corrected Coefficient, UD
114
A = Nt x L x a''
= 239 x 18 ft x 0,1963 ft2
= 844,48
Q
UD =
U D . t
= 147,13
karena nilai Ud perhitungan mendekati nilai Ud asumsi, maka data untuk
shell :
Shell = Air
ID = 17,25 inch (Tabel 9, Kern)
Baffle Space (B = ID/2) = 8,625 inch
Pass =1
Pt = 0,938 in triangular pitch
6. Perhitungan desain bagian tube
Flow Area/tube, a’t
a’t = 0,334 in2 (Tabel 10, Kern)
Nt a ' t
at =
144 n
239 0,334
=
144 1
= 0,55 ft2
Laju Alir, Gt
Gt = W/at
298.254,87
= 0,55
= 538.028,98 lb/hr.ft2
Bilangan Reynold, Ret
μ = 0,018 cp = 0,044 lb/ft hr
ID = 0,632 inch = 0,053 ft (Tabel 10, Kern)
Ret = ID.Gt/ μ
0,053 538.028,98
= 0,044
115
= 639.845,39
Dengan L/D = 341,77 diperoleh
Jh = 1.000 (Fig.24, Kern)
Nilai hi
CP = 8,140 Btu/lb.oF
k = 0,006 Btu/hr ft.oF
Prandl Number (Pr)
c. = 57,22
k
1/ 3 0,14
k Cp
hi J H
D k w
0 ,14
Koreksi viskositas diabaikan, karena
=1
w
0,006
57,22
1/ 3
hi = 1.000
0,053
= 0,207 ft2
Laju Alir, Gs
116
Gs = w/as
683.321,80
= 0,207
= 3.306.812,50 lb/hr.ft2
Bilangan Reynold, Res
de = 0,55 in (Fiq.28 Kern)
= 92.567,65
Maka:
jH = 200 (Fig.28, Kern)
Nilai ho
Cp = 17,98 Btu/lb.oF
k = 0,36 Btu/hr ft.oF
Prandl Number (Pr)
1
Cp. 3
= 816,25
k
= 306,95 Btu/hr.ft2.oF
117
9. Dirt Factor, Rd
U C U D
Rd =
U C U D
= 0,004 hr.ft2.oF/Btu
10. Pressure drop
Bagian tube
Untuk NRe = 639.845,39
Faktor friksi = 9 x 10-5 (Fig 26, Kern)
s = 0,841
f Gt 2 L n
ΔPt =
5, 22 x 10 10 x De s t
= 0,22323 psi
V2 / 2g = 0,04 (Fig 27, Kern)
ΔPr = ( 4n/s ) ( V2/2g )
= 0,190 Psi
ΔPT = ΔPt + ΔPr
= 0,414 psi
Shell Side
Res = 92.567,65
f = 0,000005 (Fig.29, Kern)
N+1 = 12 L / B = 300,52
Ds = 1,438 ft
s =1
fGs 2 Ds( N 1)
ΔPs =
5,22 1010 Des s
= 9,87 psi
118
IDENTIFIKASI
Nama Alat Cooler-01
Kode Alat C-01
Jumlah 1 buah
Operasi Kontinyu
Fungsi Menurunkan temperatur keluaran R-03
DATA DESAIN
Tipe Shell and Tube Heat Exchanger
Bahan Konstruksi Carbon Steel
Tube Side Shell Side
Jumlah 239 ID 17,25 in
Panjang 18 ft Baffle Space 8,625 in
OD 0,75 in
BWG 18
Pitch 15/16 in triangular pitch
Pass 1 Pass 1
Pt 0,414 psi Ps 9,87 psi