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MANOJ CHAUHAN SIR(IIT-DELHI)


EX. SR. FACULTY (BANSAL CLASSES)
EXERCISE–III
x tan 2x  2x tan x
Q.1 Lim is : [ JEE '99, 2 (out of 200) ]
x 0 (1  cos 2x)2
1 1
(A) 2 (B)  2 (C) (D) 
2 2
x
 x  3
Q.2 For x  R , Lim
x   = [ JEE 2000, Screening]
 x  2
(A) e (B) e 1 (C) e 5 (D) e5
sin(  cos2 x)
Q.3 Lim equals [ JEE 2001, Screening]
x 0 x2

(A) – (B)  (C) (D) 1
2

atanx  asin x
Q.4 Evaluate Lim , a > 0. [REE 2001, 3 out of 100]
x 0 tan x  sin x

(cos x  1)(cos x  e x )
Q.5 The integer n for which Lim is a finite non-zero number is
x 0 xn
(A) 1 (B) 2 (C) 3 (D) 4
[JEE 2002 (screening), 3]
sin(n x)[(a  n)n x  tan x]
Q.6 If Lim  0 (n > 0) then the value of 'a' is equal to
x 0 x2
1 n2  1
(A) (B) n2 + 1 (C) (D) None
n n
[JEE 2003 (screening)]

2 1  1  
Q.7 Find the value of Lim  (n  1) cos  n   n .
n  
[ JEE ' 2004, 2 out of 60]
   

x2
a  a2  x 2 
Q.8 Let L  lim 4 , a > 0. If L is finite, then [JEE' 2009, 3]
x 0 x4
1 1
(A) a = 2 (B) a = 1 (C) L  (D) L 
64 32

1/ x
Q.9 If lim 1  x ln(1  b 2 )   2b sin2 , b  0 and   ( , ], then the value of  is [JEE' 2011]
x 0

   
(A)  (B)  (C)  (D) 
4 3 6 2

Q.10 Let (a) and (a) be the roots of the equation [JEE' 2012]

 3
1  a  1 x2   1 a  1 x    6

1  a  1  0 where a > – 1

Then lim (a) and lim (a) are


a 0 a 0

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5 1 7 9
(A)  and 1 (B)  and 1 (C)  and 2 (D)  and 3
2 2 2 2

 x2  x  1 
Q.11 If lim   ax  b   4, then [JEE' 2012]
x 0
 x 1 
(A) a = 1, b = 4 (B) a = 1, b = – 4 (C) a = 2, b = – 3 (D) a = 2, b = 3

(1  cos 2x)(3  cos x)


Q.12 lim is equal to : [IIT Mains 2013]
x 0 x tan 4x

1 1
(A) 2 (B)  (C) (D) 1
4 2

sin(  cos2 x)
Q.13 lim is equal to : [IIT Mains 2014]
x 0 x2

(A)  (B) (C) 1 (D) – 
2

1 x
 ax  sin(x  1)  a 1 x 1
Q.14 The largest value of the non-negative integer a for which lim    is
x 1
 x  sin(x  1)  1  4
[JEE Advanced 2014]

EXERCISE–III
Q.1 C Q.2 C Q.3 B Q.4 lna Q.5 C
2
Q.6 C Q.7 1 Q.8 A, C Q.9 D Q.10 B

Q.11 B Q.12 A Q.13 A Q.14 0

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