Model Question Paper (Set-II) Physics (Senior Secondary) : Questions and Answers Questions (Section-A)
Model Question Paper (Set-II) Physics (Senior Secondary) : Questions and Answers Questions (Section-A)
Model Question Paper (Set-II) Physics (Senior Secondary) : Questions and Answers Questions (Section-A)
Q(1) ,d yacs] le:i vkfo"V lh/ks rkj ls nwjh ‘r’ ij fo|qr {ks= dh rhozrk E1 ,oa nwjh
2r ij fo|qr {ks= dh rhozrk E2 gS A E1 ,oa E2 dk vuqikr gksxk&
The electric field intensity at distances r and 2r from a long, uniformly charged
straight wire are E1 or E2 respectively. The ratio of E1 and E2 will be—
(A) 1/2 (B) 2/1 (C) 1/1 (D) None of these ( buesa ls dksbZ ugha )
Q(2) nks lsyksa dk fo|qr okgd cy Øe'k% e1 ,oa e2 gS rFkk vkarfjd izfrjks/k Øe'k% r1 ,oa
r2 gSA bu lsyksa dks Js.kh Øe esa tksM+k x;k gSA budk lerqY; fo|qr okgd cy
gksxk&
Two Cells of emfs e1 and e2, and internal resistances r1 and r2 respectively are
joined in series. Their equivalent emf will be-
Q(3) rhu izfrjks/kd ftuesa ls izR;sd dk izfrjks/k R gS] fHkUu&fHkUu rjhdksa ls la;ksftr fd;s
x;s gSaA buesa ls dkSu izkIr ugha gks ldrk?
Three resistors of resistance R each are combined in various ways. Which of
the following cannot be obtained?
Q(4) ,d nl vkse rkj dh yEckbZ dks [khapdj rhxq.kk yEck dj fn;k tkrk gSA rkj dk
u;k izfrjks/k gksxk&
A 10 ohm wire is stretched so that its length becomes three times its original
length. The new resistance of the wire will be-
Q(5) ,d 220V, 1000W cYc dks 110V lzksr ls tksM+k tkrk gSA cYc ds }kjk [kir dh
xbZ 'kfDr gksxk&
A 220V, 1000W Bulb is connected to a 110V supply. The power consumed
by bulb will be-
Q(6) fddZgkQ dk izFke fu;e ¼∑I=0½ ,oa f}rh; fu;e ¼∑IR=∑E½ Øe'k% vk/kkfjr gS&
Kirchhoff’s first law ¼∑I=0½ and second law ¼∑IR=∑E½ are respectively based
on-
Q(7) ;fn fdlh pqEcd dks pqEcdh; ;kE;ksÙkj esa bl rjg j[kk tk, fd mldk mŸkjh /kzqo
mŸkj dh vksj gks rks mnklhu fcUnq dh la[;k gksxh&
If a magnet is kept in magnetic meridian with its North Pole pointing north,
then number of neutral points will be-
Q(8) izR;korhZ /kkjk ifjiFk ds LCR Js.kh la;kstu esa oksYVst izR;sd L,C,R ?kVd esa 50
oksYV gSA oksYVst LC la;kstu ds chp gksxk&
Q(9) izR;korhZ /kkjk ifjiFk esa ;fn /kkjk I ,oa oksYVst ds chp dykUrj α gks rks /kkjk dk
okVghu ?kVd gksxk&
If an ac circuit, the phase difference between current I and voltage be α, then
wattless component will be-
(A) ICosα (B) ISinα (C) Itanα (D) None of these¼buesa ls dksbZ ugha½
Q(10) ;fn fdlh izR;korhZ /kkjk ifjiFk dh ;FkkFkZ vkSj vkHkklh 'kfDr;k¡ Øe'k% PT ,oa PA
gks rks 'kfDr xq.kkad gksxk&
If in an ac circuit true power and apparent power be PT and PA, then power
factor will be-
Q(11) tc fdlh dqaMyh ds fudV fdlh pqEcd dk nf{k.kh /kzqo nwj ys tk;k tkrk gS rc
mlesa mRiUu izsfjr fo|qr /kkjk dh fn'kk gksrh gS&
When South Pole of magnet close to a coil is taken away from the coil, then
the direction of induced current in the coil-
(A) okekoÙkZ ¼Anticlockwise½
(C) dHkh okekoÙkZ dHkh nf{k.kkoÙkZ ¼Sometimes anticlockwise and sometimes clockwise)
Q(12) ,d pqEcd ,d can pkyd ds fudV fLFkr gSA pkyd esa /kkjk mRiUu dh tk ldrh
gSA ;fn&
A magnet is near a close conductor. The current may be produced in the
conductor if-
(A) dsoy pqEcd xfr'khy gks ¼Only magnet is in motion½
(B) dsoy pkyd xfr'khy gks ¼Only Conductor is in motion½
(C) pqEcd vkSj pkyd nksauks xfr'khy gks ¼Both magnet and conductor be in
motion½
(D) Pkkyd vkSj pqEcd ds chp vkisf{kd xfr gks ¼Relative motion between
conductor and magnet½
Q(15) ,d irys ysal dks tc 1-6 vioŸkZukad okys nzo esa Mqck;k tkrk gS] rc ysal ugha
fn[kkbZ iM+rk gSA ysal dk vioŸkZukad&
A thin lens is not visible when lens is immersed in a liquid of refractive index
1.6. The refractive index of liquid is-
Q(16) nks lery niZ.k ds chp esa ,d oLrq dks j[kk x;k gSA ;fn niZ.kksa ds chp dk dks.k
600 gks rks egŸke izfrfcEcksa dh la[;k gksxh&
An object is placed between two plane mirrors inclined to each other at an
angle of 600. The maximum number of images seen will be-
Q(20) -1.5D ,oa +2.5D {kerk ds nks ysal lEidZ esa j[ks x;s gSaA bl la;kstu dh Qksdl
nwjh gksxh&
Two lenses of power -1.5D and +2.5D are placed in contact. The focal length
of combination will be-
Q(21) ,d [kxksyh; nwjchu dh yEckbZ 16cm gS vkSj blds vko/kZu {kerk 3 gSA ysalksa dh
Qksdl nwfj;k¡ gksx
a h&
The length of an astronomical telescope is 16cm and its magnifying power is
3. The focal length of the lenses will be-
(A) n=5 to n=4 (B) n=4 to n=3 (C) n=3 to n=2 (D) n=2 to n=1
Q(25) ,d ijek.kq ;k vkW;u dk ewy voLFkk esa ÅtkZ -54.4ev. ;g gks ldrk gS&
The energy of an atom (or ion) in its ground state is -54.4ev. It may be-
(A)107
(B) 1017
(C) 1024
(D)1027
5B
10
+ 2He4 → 7N13 +-----
Q(30) ‘NAND’ xsV ds nksuksa fuos'k tksM+ fn;s tkrs gSa rks ;g cu tkrk gS&
Two inputs of ‘NAND’ Gate are connected together. This Gate is equivalent
to-
(A) OR GATE (B) AND GATE (C) NOT GATE (D)XOR GATE
Q(31) ,d v)Zpkyd Mk;ksM esa p-side dks i`Foh ls ,ao n-side dks -2V ls tksM+k tkrk
gSA Mk;ksM&
In a semiconductor diode, p-side is earthed and n-side is applied to a potential
of -2V, the diode shall –
Q(33) okgd ¼jsfM;ks½ rjaxksa ij fdlh lwpuk ds v/;kjksi.k dh izfØ;k dk uke gS&
The process of super-position of an information on a carrier wave is called-
Q(34) mixzg lapkj.k esa fo|qr pqEcdh; rjax dk dkSu lk Hkkx iz;qDr gksrk gS&
Which of the following part of electromagnetic wave is used for satellite
communication?
Q(35) jsfM;ks ,ao Vsfyfotu izlkj.k esa lwpuk ladsr dk :i gksrk gS&
The form of information signal used in radio and television transmission-
(B) fMftVy flXuy (Digital Signal) ,ao ,ukykWx flXuy (Analog Signal)
Q(1) ,d Xykl&NM+ dks flYd ls jxM+us ij nksukas gh vkfo"V gks tkrs gSaA crk,¡ fd ;s ?kVuk,¡
vkos'k laj{k.k ds fu;e ds vuqdwy dSls gS?
When a glass is rubbed with silk, both of them get charged. Show how this event
is consistent with the law of charge conservation?
Q(3) ,d pqEcdh; {ks= leku fn'kk esa jgrs gq, nwjh ds lkFk detksj gksrk tk jgk gSA ,d
vkos'k fcuk fopyu ds bl {ks= ls xqtj ldrk gS] dSls? O;k[;k djsaA
A magnetic field is becoming weaker with distance but is directed as before. How
will a charge be fired to show no deviation? Explain.
Q(4) xeZ rkj ;a= dk O;ogkj izR;koŸkhZ /kkjk ,oa lh/kh /kkjk] nksuksa ds eku fudkyus esa vkrk gS]
D;ksa ?
Hot wire instruments can be used to measure both alternating current and direct
current. Why?
Q(5) izR;koŸkhZ /kkjk vkSj lh/kh /kkjk esa dkSu T;knk [krjukd gS D;ksa ?
Q(6) fHkUu izdkj ds fo|qr pqEcdh; rjaxksa dks rjaxnS/;Z ds vuqlkj ltk;a&
s
Arrange the different type of electromagnetic waves in accordance with
wavelength-
Q(10) izdk'k&fo|qr izHkko D;k gS? izdk'k&fo|qr izHkko ds fu;e D;k gS?
What is Photo electric effect? What are the laws of photo electric effect?
Q(11) gkbMªkstu ijek.kq dk ewy voLFkk ,oa mŸksftr voLFkkvksa dh ÅtkZvksa dk eku fy[ksa A
Write the energy value of hydrogen atom in ground state and excited state.
Q(14) /kkfRod pkyd] v}Zpkyd ,oa dqpkyd dk oxhZdj.k oS|qr pkydrk vFkok izfrjks/kdrk
ds vk/kkj ij djsaA
Classify the metallic conductor, semiconductor and Insulator on the basis of
electrical conductivity or resistivity.
Q(1) ,dleku fo|qr {ks= esa fo|qr f}/kzqo dh fLFkfrt ÅtkZ dh x.kuk djsaA fo|qr f}/kzqo
fdl ifjfLFkfr esa vLFkkbZ larqYku dks izkIr djsxk?
Find potential energy of an electric dipole in a uniform electric field. What is the
condition of unstable equilibrium of electric dipole?
vFkok¼OR½
vlarqfyr go~hVLVksu fczt ds XkSyosuksehVj ls izokfgr /kkjk dh x.kuk djas A
Calculate current through the galvanometer of an unbalanced Wheatstone
Bridge.
Q(2) pqEcdh; {ks= esa /kkjkokgh pkyd ij dk;Zdkjh cy dh x.kuk djaAs ¶ysfeax ds ck;sa gkFk
dk fu;e fy[ksa A
Calculate the force on a current carrying conductor in a magnetic field. Write
the Fleming’s left hand rule.
vFkok¼OR½
/kkjkokgh dqaMyh dk pqEcdh; f}/kzqo vk?kw.kZ D;k gS ? ,d vuar yEckbZ okys lh/ks rkj esa
izokfgr gksus okyh /kkjk ds dkj.k pqEcdh; {ks= dh x.kuk djsa A
What is the magnetic dipole moment of a current carrying coil? Calculate the
magnetic field due to an infinitely long straight current carrying wire.
Q(3) oLrq rFkk izfrfcEcksa dh nwfj;ksa ds chp laca/k crkus okys lw= dks LFkkfir djsa tc fd n1
rFkk n2 vioŸkZukad okys ek/;eksa dks vyx djus okyh mŸky lrg ij vioŸkZu gksrk gSA
Deduce the formula connecting the positions of object and image when refraction
takes place at a convex surface separating two media of refractive indices n1 and
n2.
vFkok¼OR½
‘NOR’ Gate (xsV) ls izkIr djsa A
(i) ‘NOT’ Gate (xsV) (ii) ‘OR’ Gate (xsV) (iii) ‘AND’ Gate (xsV)
Obtain:-
From‘NOR’ Gate
Answers of Set 2 (Physics)
Answer Key for Objective Questions ( )
Ans(1) jxM+us ls iwoZ] Xykl NM+ ,oa flYd ij vkos'kkas dk ;ksx ¾ 'kwU;
jxM+us ds ckn] Xykl NM+ ,oa flYd ij vkos'kkas dk ;ksx ¾ (+ne) + (-ne)
¾ 0 ¼'kwU;½
vr% ;g ?kVuk vkos'k laj{k.k ds fl)kar ds vuqlkj gS A
Before rubbing, Sum of charges on glass rod and silk ¾ Zero
After rubbing, sum of charges on glass rod and silk ¾ (+ne) + (-ne)
¾ 0 Zero
Hence this event is in consistent with the law of conservation of charge.
Ans(2) dkcZu izfrjks/kdksa ds izfrjks/k dk eku vkSj mldh izfr'kr fo'oluh;rk lwfpr djus
ds fy, o.kZdksM dk mi;ksx fd;k tkrk gS A
Colour code is used to indicate the value of resistance of carbon resistors
and its percentage reliability.
Ans(4) xeZ rkj&;a= /kkjk ds Å"eh; izHkko ij dk;Z djrk gSA /kkjk dk Å"eh; izHkko /kkjk
ds oxZ dk lekuqikrh gksrk gSA rkj esa izR;korhZ /kkjk ;k fn"V /kkjk ikfjr djkus
ij] nksuksa gkyr esa Å"ek mRiUu gksrh gS ftlds dkj.k rkj dh yEckbZ esa o`f)
gksrh gSA rkj dh yEckbZ ekidj /kkjk dk eku ekywe fd;k tkrk gSA
Hotwire instrument based on Heating effect of current. In Heating effect of
current, Heat is proportional to square of current.
Heat is produced in wire when alternating current or direct current passes
through it. Length of wire increases due to development of heat. Electric
current is measured by measuring the length.
Ans(5) leku oksYVst ds fy;s izR;koŸkhZ /kkjk lh/kh /kkjk ls T;knk [krjukd gS D;ksfa d
izR;koŸkhZ oksYVst dk f'k[kj eku lh/kh /kkjk ds oksYVst ls T;knk gksrk gS A
The alternating current is more dangerous than direct current of the same
voltage. It is because the peak value of alternating voltage is more than the
indicated value.
Ans(6)
fo/kqr&pqEcdh; rjax rjaxnS/;Z ¼Øe es½a
(Electromagnetic wave) (Wavelength) (In Order)
1. Gamma rays (xkek fdj.kas) -12
10 m
2. X-rays (X fdj.ksa) 10-10m
3. U-V rays (ijkcSaxuh fdj.kas) 10-8m
4. Visible rays (n`"; fdj.kas) 10-7m
5. Infrared rays(vojDr fdj.kas) 10-6m
6. Microwave(lw{e rjaxas) 10-4m to 100m
7. Radiowave(jsfM;ks rjaxas) 100m to Several km (dbZ fdyksehVj)
Ans(8)
O;frdj.k fooŸkZu
(Interference) (Diffraction)
1. O;frdj.k nks dyk lEcU/k fooŸkZu dh ?kVuk ,d gh rjaxkxz ls
lzksrksa ls vkusokyh rjaxksa ds mRiUu f}rh;d rjaxksa dk v/;kjksi.k gSA
v/;kjksi.k ds dkj.k gksrk gSA Diffraction is due to superposition
Interference is due to of secondary waves coming from
super position of Waves same wavefront.
coming from two coherent
sources.
2. blesa lHkh fÝat leku rhozrk blesa lHkh fÝat leku rhozrk ds ugha
ds gksrs gaSA gksrs gSaA
All fringes are equally All fringes are not equally bright in
bright in it. it.
Ans(10) ;fn /kkrq ds lrg ij mfpr rjaxnS/;Z dk izdk'k vkifrr gksrk gS rks /kkrq ds lrg
ls bysDVªkWu dk mRltZu gksrk gSA bl ?kVuk dks izdk'k&fo/kqr izHkko dgk tkrk
gSA mRlftZr bysDVªkWu dks izdk'k bysDVªkWu dgk tkrk gS A
izdk'k fo/kqr izHkko ds fu;e%
izFke 1st izdk'k bysDVªkWu dk egŸke osx ¼blfy, egŸke xfrt ÅtkZ½
vkifrr izdk'k dh vko`fŸk ds lkFk c<+rh gSA
f}rh; 2nd izfr ls0 mRlftZr izdk'k bysDVªkWu dh la[;k izdk'k ds rhozrk ds vuqØekuqikrh
gksrh gSA
The emission of electrons from metal surface under the action of light of
appropriate wavelength, is called photoelectric effect. The emitted
photoelectrons are called photoelectrons.
1st law The maximum velocity (hence, the maximum kinetic energy) of the
photoelectron increases with increase in frequency of incident light.
2nd law The number of electrons emitted per second is directly proportional to
intensity of incident light.
Ans(15)
ekWM~;wy's ku ¼Modulation½ fMekWM~;wy's ku (Demodulation)
1. JO; ladsr dks ,d mPp vko`fŸk dh okgd rjax JO; rjax dks ekWMqysVsM rjax ls
ij izfrjksi.k ;k v/;kjksi.k ds izØe dks ekWM~;wys'ku i`Fkd~ djus ds izØe dks
dgrs gSaA fMekWM~;wy's ku dgk tkrk gSA
Answer of OR
,d vlarqfyr g~ohVLVksu fp= esa fn[kk;k x;k gS
(Unbalanced Wheatstone Bridge is shown in the figure.)
Ans.(2)
Stretch the thumb, forefinger and middle finger of the left hand
such that they are mutually perpendicular to each other. If middle
finger points in the direction of current and forefinger points in
the direction of magnetic field, then direction along which thumb
points gives the direction of force on the current carrying
conductor.
Answer of OR
→ →
B . dl = 𝜇 0I
B 2𝜋r =𝜇 0I
B = 𝜇 0I/2𝜋r
Suppose current 'I' flows through a straight wire of infinite length. Magnetic
field 'B' is to be calculated at a distance r at point 'P' due to current in the wire.
Using Ampere Circuital's law
→ →
B . dl = 𝜇0I
B 2𝜋r = 𝜇 0I
B = 𝜇0I/2𝜋r
Ans.(3)