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Boundray Wall Design Data Ganj Basoda

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Design of Boundary Wall

The boundary wall will be made of brick work. It is supported by bottom plinth beams.These beams a
columns which are supported by reinforced
concrete foundation to transfer the load to the soil beneath.
2700 PLINTH BEAM

950

300

200 300

Grade of concrete (M-20) 20


Grade of steel (Fe-415) 415
Size of column B(mm) 200
D(mm) 300
Clear Span of brick wall 2700
Size of plinth beamB(mm) 300
D(mm) 300

Loads Calculation :
a) Dead Load
Unit wt. of reinforced concrete (kN/m3)
25
Unit wt. of brick (kN/m3) 20
Unit wt. of soil (kN/m3) 18 200
I) Self wt. of brick(kN/m) 1.60
ii) Self wt.of M.S.angle & accessories (kN/m 0.95
iii) Self wt. of 300 x 300 tie beam (kN/m) 2.25 200
iv) Self wt. of stone coping (kN/m) 0.3
b) Wind Load
Wind loads are calculated as per IS : 875 - Part 3. Design wind speed, Vz = Vb.k1.k2.k3.
Basic Wind Speed Vb ( m/s ) = 39
Terrian Category 1 ; Building Class C
As per Table 1; IS : 875 - Part 3 k 0.9
As per Table 2; IS : 875 - Part 3, k 0.99
As per Clause 5.3.3; IS : 875 - Part 3, 1
Design Wind Velocity Vz ( m/sec 34.749
Design Wind pressure pz = 0.6 (Vz)2(KN/sqm)= 1.45
(Considering Drag Force)
Total design pressure intensity (kN/m) 3.91
Design of Column :
Dead load on column
Due to wall & plinth beam (kN) 12.75
Self wt. of column (kN) 3.53
Axial load on one column (kN) 16.28

Wind load on influence area of 2.7m x 1.6m will act at the c.g. of the exposed area
Wind load (kN) 6.26
Wind load Moment at the base of
column = 6.26 x (0.8 + 0.95 ) kN-m 10.96

length of column (m) 1.6


Minimum eccentricities :
e = L/500 + D/30
ex (mm) 9.87
ey (mm) 13.20
Adopt ex = 20 mm ; ey = 20 mm (Clause 25.4 - IS : 456 - 2000)
Moments from minimum eccentricity consideration :
Muex = 1.5 * 16.28 * 20/1000 (kN-m) 0.49
Muey = 1.5 * 16.28 * 20/1000 (kN-m) 0.49
Effective length (le)
B larger direction (as per IS Code) 0.28
B shorter direction (as per IS Code) 0.65
Effective length in larger direction (mm) 1607
Effective length in shorter direction (mm) 1372.5

Slenderness ratios are : 6.9


5.4
Additional Moment due to slenderness:
Factored Max (kN-m) 0.11
Factored May (kN-m) 0.12
Total moment (Ultimate moment for design of column) :
Mux = (1.5 * 10.96 + 0.11) (N-mm) 16.54
Muy = (0.49 + 0.12) (N-mm) 0.60
Ultimate axial force for design
Pu = 1.5 x 16.28(kN) 24.42
Clear cover (mm) 40
Diameter of bar(mm) for column 12
d' 46
B (mm) 200
D (mm) 300
d'/B 0.230
d'/D 0.153
Pu / fckbD 0.020

Say, p 0.60%
Ag (sq.mm) 60000 1030.44
Puz / Ag (N/mm 2)
Chart 63; SP : 16 14.8
Puz (kN) 888
p / fck (Say, reinforcements
distributed equally on two sides) 0.03
d'/b 0.230
Muy1 / fckb2D =0.055 Chart 38; SP : 1 0.055
Muy1 (kN-m) 13.20
d'/D 0.153
Mux1 / fckbD2 = 0.075 Chart 36; SP : 16 0.075
Mux1 (kN-m) 27.00

Hence,
Mux / Mux1 0.613
Muy / Muy1 0.046
Pu / Puz 0.028

For above values of (Pu / Puz) & (Muy / Muy1)


Mux / Mux1 Chart 64; SP : 16 0.97
Pt = p =0.6 %
Reinforcement required (mm2) 360
No. of 12 Dia. Reinforcement bar 4
Tie beam 8 φ @ 175 c/c
Design of Tie Beam (B=300 x D=300) :
The plinth beam will experience downward load due to
self wt & brick wall including stone coping at top

Weight of brick work (kN/m) 1.60


Self weight of beam (kN/m) 2.25
Self wt. of stone coping (kN/m) 0.3
Total (kN/m) 4.15
L (m) 2.7
Max Vertical moment (kNm) 3.03
Factored Mu (kN-m) 4.54
Clear Cover for Tie beam (mm) 40.00
Dia of bar (mm) 12.00
Effective Depth d (mm) 254
Mu/bd2 (N/mm2) 0.17
From SP:16,Table 3 for M 20 and fy 415, pt 0.15%
Ast required (mm2) 135
For shear, shear force Vu (kN) 8.40
Vu/bd 0.09
Maximum Spacing = 0.75 d Clause 26.5.1.5 IS : 456 - 2000
No. of bars 2
Provide 2-12φ (top-althr) & 2-12φ (bottom-althr) with 2L-8φ @ 175 mm c/c
nth beams.These beams are tied with
ed

PLINTH BEAM

FOUNDATION

1.6

2.4 2.895

Vb.k1.k2.k3.
F.G.L

TIE BEAM 300 x 300

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