TOP 50 Quadratic Equation Questions for Bank PO & Clerk Exams

II. 17y2 +22y + 9 = 13y2 + 10y

Directions (1 – 5): In the following questions, two 8)
equations I and II are given. You have to solve both the I. 7x2 + 37x + 36 = 0
equations and give Answer as, II. 9y2 + 35y + 24 = 0
a) If x > y 9)
b) If x ≥ y I. 5x – 4y = -12
c) If x < y II. 3x + 5y = -59
d) If x ≤ y 10)
e) If x = y or the relation cannot be established I. 15x2 + 68x + 77 = 0
1) II. 3y2 + 29y + 68 = 0
I. 12x2 – 40x + 32 = 0
II. 8y2 – 40y + 48 = 0 Directions (11 – 15): In the following questions, two
2) equations I and II are given. You have to solve both the
I. 9x – 7y = 15 equations and give Answer as,
II. 3x – y = – 3 a) If x > y
3) b) If x ≥ y
I. 12x2 + 40x + 32 = 0 c) If x < y
II. 8y2 + 40y + 42 = 0 d) If x ≤ y
4) e) If x = y or the relation cannot be established
I. 4x2 – 7x – 57 = 0 11)
II. 5y2 – 6y – 63 = 0 I. 5x2 + 16x – 16 = 0
5) II. 4y2 + 3y – 22 = 0
I. 12x2 + 17x – 57 = 0 12)
II. 4y2 -7y – 36 = 0 I. x2 = 4624
II. y3 – 248 = 373000
Directions (6 – 10): In the following questions, two 13)
equations I and II are given. You have to solve both the I. x2 – 4x – 621 = 0
equations and give Answer as, II. y2 – 34y + 285 = 0
a) If x > y 14)
b) If x ≥ y I. 6x + 5y = √2809
c) If x < y II. 5x + 7y = 64
d) If x ≤ y 15)
e) If x = y or the relation cannot be established I. x2 + 7x – 330 = 0
6) II. y = (194481)1/4
I. (x12/7 ÷ 16) = (49 ÷ x2/7)
II. y31/7 × y4/7 × 9 = 324 × y3 Directions (16 – 20): In the following questions, two
7) equations I and II are given. You have to solve both the
I. 15x2 – 40x + 16 = 10x2 – 22x equations and give Answer as,
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 TOP 50 Quadratic Equation Questions for Bank PO & Clerk Exams
a) If x > y I. 2x2 – 302 = 420
b) If x ≥ y II. y – √361 = 0
c) If x < y
d) If x ≤ y Directions (26 – 30): In the following questions, two
e) If x = y or the relation cannot be established equations I and II are given. You have to solve both the
16) equations and give Answer as,
I. 5x2 + 16x – 16 = 0 a) If x > y
II. 4y2 + 3y – 22 = 0 b) If x ≥ y
17) c) If x < y
I. x2 = 4624 d) If x ≤ y
II. y3 – 248 = 373000 e) If x = y or the relation cannot be established
18) 26)
I. x2 – 4x – 621 = 0 I. 5x + 6y = 21
II. y2 – 34y + 285 = 0 II. 4x + 5y = 11
19) 27)
I. 6x + 5y = √2809 I. 2x2 + 13x + 20 =0
II. 5x + 7y = 64 II. 3y2 – y – 10 = 0
20) 28)
I. x2 + 7x – 330 = 0 I. 5x2 + 12x – 9 = 0
II. y = (194481)1/4 II. 6y2 – 13y – 8 = 0
29)
Directions (21 – 25): In the following questions, two I. 5x2 + 3x -14 = 0
equations I and II are given. You have to solve both the II. 5y2 + 8y – 21 = 0
equations and give Answer as, 30)
a) If x > y I. 5x2 – 6x – 56 = 0
b) If x ≥ y II. 6y2 + 9y – 42 = 0
c) If x < y
d) If x ≤ y Directions (31 – 35): In the following questions, two
e) If x = y or the relation cannot be established equations I and II are given. You have to solve both the
21) equations and give Answer as,
I. x2 – 9x – 112 = 0 a) If x > y
II. y2 + 26y – 87 = 0 b) If x ≥ y
22) c) If x < y
I. 12x2 + 37x + 28 =0 d) If x ≤ y
II. 14y2 + 39y + 27 = 0 e) If x = y or the relation cannot be established
23) 31)
I. 4x2 + 23x – 72 = 0 I. 3x2 +14x +15 =0
II. 5y2 – 28y + 32 = 0 II. 3y2 -13y +14 =0
24) 32)
I. x2 + 5√7 + 42 = 0 I. 4x2 – 6x – 18 = 0
II. y2 + 6√7 + 56 = 0 II. 5y2 + 6y – 27 = 0
25) 33)

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 TOP 50 Quadratic Equation Questions for Bank PO & Clerk Exams
I. x2 – 23x + 102 = 0 41)
II. y2– 24y – 256 = 0 I. 7x2 + 27x + 18 = 0
34) II. 9y2+ 23y – 12 = 0
I. 5x – 2y = -11 42)
II. 3x + 5y = -19 I. 7x – 2y = 25
35) II. 5x + 3y = 9
I. x = ∜4096 43)
II. y = ∛729 I. 6x2 + 17x – 58 = 0
II. 5y2 – 2y – 72 = 0
Directions (36 – 40): In the following questions, two 44)
equations I and II are given. You have to solve both the I. 4x2 + 40x + 64 = 0
equations and give Answer as, II. 3y2 + 44y + 153 = 0
a) If x > y 45)
b) If x ≥ y I. 5x2 + 27x – 56= 0
c) If x < y II. 7y2 + 11y – 6 = 0
d) If x ≤ y
e) If x = y or the relation cannot be established Directions (46 – 50): In the following questions, two
36) equations I and II are given. You have to solve both the
I. 3x2 – 18x + 27 = 0 equations and give answer as,
II. 5y2 + 11y – 36 = 0 a) If x > y
37) b) If x ≥ y
I. 4x – 5y = 28 c) If x < y
II. 3x + 4y = -10 d) If x ≤ y
38) e) If x = y or the relation cannot be established
I. x2 + 18x – 115 = 0 46)
II. y2 + 21y + 98 = 0 I. x2 – 12x + 36 = 0
39) II. 5y2 + 4y – 12 = 0
I. x2 – 12x – 64 = 0 47)
II. y2 + 13y + 42 = 0 I. 2x2 + 12x + 16 = 0
40) II. 3y2 -7y – 6 = 0
I. 2x2 + 9x – 45 = 0 48)
II. 4y2 + 19y + 22 = 0 I. 7x + 2y = -13
II. 5x – 4y = 7
49)
Directions (41-45): In the following questions, two I. x2 + 2x – 15 = 0
equations I and II are given. You have to solve both the II. y2 + y – 56 = 0
equations and give Answer as, 50)
a) If x > y I. √25 x + √5625 = 0
b) If x ≥ y II. (243)1/5 y + (1728)1/3 = 0
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established Answers:

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 TOP 50 Quadratic Equation Questions for Bank PO & Clerk Exams
1) Answer: d) 5) Answer: e)
I. 12x2 – 40x + 32 = 0 I. 12x2 + 17x – 57 = 0
12x2 – 24x – 16x + 32 = 0 12x2 – 36x + 19x – 57 = 0
12x(x – 2) – 16(x – 2) = 0 12x(x – 3) + 19(x – 3) = 0
(12x – 16) (x – 2) = 0 (12x + 19) (x – 3) = 0
X = 16/12, 2 = 1.33, 2 X = -19/12, 3 = -1.58, 3
II.8y2 – 40y + 48 = 0 II. 4y2 -7y – 36 = 0
8y2 – 16y – 24y + 48 = 0 4y2 -16y + 9y – 36 = 0
8y(y – 2) – 24(y – 2) = 0 4y(y – 4) + 9(y – 4) = 0
(8y – 24) (y – 2) = 0 (4y + 9) (y – 4) = 0
Y = 3, 2 Y = – 9/4, 4 = 2.25, 4
x≤y Can’t be determined
2) Answer: a) 6) Answer: e)
9x – 7y = 15–> (1) I. (x12/7 ÷ 16) = (49 ÷ x2/7)
3x – y = – 3—> (2) X12/7 × x2/7 = 49 × 16
By solving the equation (1) and (2), we get, X14/7 = 49 × 16
X = -3, y = -6 X2 = 49 × 16
x> y X = + (7*4), – (7*4) = +28, -28
3) Answer: e) II. y31/7 × y4/7 × 9 = 324 × y3
I. 12x2 + 40x + 32 = 0 Y31/7 + 4/7 –3 = 324/9
12x2 + 24x + 16x + 32 = 0 Y2 = 36
12x(x + 2) + 16(x + 2) = 0 Y = 6, -6
(12x + 16) (x + 2) = 0 Can’t be determined
X = -16/12, -2 = -1.33, -2 7) Answer: a)
II. 8y2 + 40y + 42 = 0 I. 15x2 – 40x + 16 = 10x2 – 22x
8y2 + 12y + 28y + 42 = 0 5x2 – 18x + 16 = 0
4y (2y + 3) + 14(2y + 3) = 0 5x2 -10x – 8x + 16 = 0
(4y + 14) (2y + 3) = 0 5x(x – 2) -8(x – 2) = 0
Y = -14/4, -3/2 = -3.5, -1.5 (5x – 8) (x – 2) = 0
Can’t be determined X = 8/5, 2 = 1.6, 2
4) Answer: e) II. 17y2 +22y + 9 = 13y2 + 10y
I. 4x2 – 7x – 57 = 0 4y2 + 12y + 9 = 0
4x2 +12x – 19x – 57 = 0 4y2 + 6y + 6y + 9 = 0
4x(x + 3) – 19(x + 3) = 0 2y (2y + 3) + 3(2y + 3) = 0
(4x – 19)(x + 3) = 0 (2y + 3) (2y + 3) = 0
X = 19/4, -3 = 4.75, – 3 Y = -3/2, -3/2 = -1.5, -1.5
II. 5y2 – 6y – 63 = 0 x> y
5y2 + 15y – 21y – 63 = 0 8) Answer: e)
5y(y + 3) – 21(y + 3) = 0 I. 7x2 + 37x + 36 = 0
(5y – 21) (y + 3) = 0 7x2 + 28x + 9x + 36 = 0
Y = 21/5, -3 = 4.2, -3 7x (x + 4) +9(x + 4) = 0
Can’t be determined (7x + 9)(x + 4) = 0

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 TOP 50 Quadratic Equation Questions for Bank PO & Clerk Exams
X = -9/7, -4 = -1.28, -4 y = 72
II. 9y2 + 35y + 24 = 0 x<y
9y2 + 27y + 8y + 24 = 0 13) Answer: e)
9y(y + 3) + 8(y + 3) = 0 I. x2 – 4x – 621 = 0
(9y + 8) (y + 3) = 0 (x +23) (x – 27) = 0
Y = -8/9, -3 = -0.89, -3 X = -23, 27
Can’t be determined II. y2 – 34y + 285 = 0
9) Answer: c) (y – 19)(y – 15) = 0
5x – 4y = -12 —> (1) Y = 19, 15
3x + 5y = -59 —> (2) Can’t be determined
By solving the equation (1) and (2), we get, 14) Answer: c)
X = -8, y = -7 I. 6x + 5y = √2809
x< y 6x + 5y = 53 -à(1)
10) Answer: a) II. 5x + 7y = 64
I. 15x2 + 68x + 77 = 0 5x + 7y = 64 –à(2)
15x2 + 35x + 33x + 77 = 0 By solving the equation (1) and (2), we get,
5x (3x + 7) +11 (3x + 7) = 0 X = 3, y = 7
(5x + 11) (3x + 7) = 0 x< y
X = -11/5, -7/3 = -2.2, -2.33 15) Answer: c)
II. 3y2 + 29y + 68 = 0 I. x2 + 7x – 330 = 0
3y2 + 12y + 17y + 68 = 0 (x – 15) (x + 22) = 0
3y(y + 4) + 17(y + 4) = 0 X = 15, -22
(3y + 17) (y +4) = 0 II. y = √441
Y = -17/3, -4 = – 5.67, -4 Y = 21
x> y x< y
11) Answer: e) 16) Answer: e)
I. 5x2 + 16x – 16 = 0 I. 5x2 + 16x – 16 = 0
5x2 + 20x – 4x – 16 = 0 5x2 + 20x – 4x – 16 = 0
5x(x + 4) – 4 (x + 4) = 0 5x(x + 4) – 4 (x + 4) = 0
(5x – 4) (x + 4) = 0 (5x – 4) (x + 4) = 0
X = 4/5, -4 = 0.8, -4 X = 4/5, -4 = 0.8, -4
II. 4y2 + 3y – 22 = 0 II. 4y2 + 3y – 22 = 0
4y2 -8y + 11y – 22 = 0 4y2 -8y + 11y – 22 = 0
4y(y – 2) + 11 (y – 2) = 0 4y(y – 2) + 11 (y – 2) = 0
(4y + 11) (y – 2) = 0 (4y + 11) (y – 2) = 0
Y = -11/4, 2 = -2.75, 2 Y = -11/4, 2 = -2.75, 2
Can’t be determined Can’t be determined
12) Answer: c) 17) Answer: c)
I. x2 = 4624 I. x2 = 4624
X = 68, -68 X = 68, -68
II. y3 – 248 = 373000 II. y3 – 248 = 373000
y3 = 373000 + 248 = 373248 y3 = 373000 + 248 = 373248

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 TOP 50 Quadratic Equation Questions for Bank PO & Clerk Exams
y = 72 X = -7/4, -4/3 = -1.75, -1.33
x<y II. 14y2 + 39y + 27 = 0
18) Answer: e) 14y2 + 21y + 18y + 27 = 0
I. x2 – 4x – 621 = 0 7y(2y + 3) + 9(2y + 3) = 0
(x +23) (x – 27) = 0 (7y + 9) (2y + 3) = 0
X = -23, 27 Y = -9/7, -3/2 = -1.28, -1.5
II. y2 – 34y + 285 = 0 Can’t be determined
(y – 19)(y – 15) = 0 23) Answer: e)
Y = 19, 15 I. 4x2 + 23x – 72 = 0
Can’t be determined 4x2 + 32x – 9x – 72 = 0
19) Answer: c) 4x (x + 8) – 9(x + 8) = 0
I. 6x + 5y = √2809 (4x – 9) (x + 8) = 0
6x + 5y = 53 ->(1) X = 9/4, -8 = 2.25, -8
II. 5x + 7y = 64 II. 5y2 – 28y + 32 = 0
5x + 7y = 64 –>(2) 5y2 – 20y – 8y + 32 = 0
By solving the equation (1) and (2), we get, 5y(y – 4) – 8 (y – 4) = 0
X = 3, y = 7 (5y – 8) (y – 4) = 0
x< y Y = 8/5, 4 = 1.6, 4
20) Answer: c) Can’t be determined
I. x2 + 7x – 330 = 0 24) Answer: e)
(x – 15) (x + 22) = 0 I. x2 + 5√7 + 42 = 0
X = 15, -22 x2 + 3√7x + 2√7x + 42 = 0
II. y = √441 x (x + 3√7) + 2√7 (x + 3√7) = 0
Y = 21 (x + 2√7) (x + 3√7) = 0
x<y X = – 2√7, -3√7
21). Answer: e) II. y2 + 6√7 + 56 = 0
I. x2 – 9x – 112 = 0 y2 + 4√7y + 2√7y + 56 = 0
x2 – 16x + 7x – 112 = 0 y(y + 4√7) +2√7 (y + 4√7) = 0
x(x – 16) + 7(x – 16) = 0 (y + 2√7) (y + 4√7) = 0
(x + 7) (x – 16) = 0 Y = -2√7, -4√7
X = -7, 16 Can’t be determined
II. y2 + 26y – 87 = 0 25) Answer: d)
y2 + 29y – 3y – 87 = 0 I. 2x2 – 302 = 420
y (y + 29) – 3(y + 29) = 0 2x2 = 302+ 420
(y – 3) (y + 29) = 0 2x2 = 722
Y = 3, -29 X2 = 361
Can’t be determined X = 19, -19
22) Answer: e) II. y – √361 = 0
I. 12x2 + 37x + 28 =0 Y = √361
12x2 + 16x + 21x + 28 =0 Y = 19
4x(3x + 4) + 7(3x + 4) = 0 x≤y
(4x+ 7) (3x + 4) = 0 26) Answer: a)

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 TOP 50 Quadratic Equation Questions for Bank PO & Clerk Exams
5x + 6y = 21—à (1) I. 5x2 – 6x – 56 = 0
4x + 5y = 11—à(2) 5x2 – 20x + 14x – 56 = 0
By solving the equation (1) and (2), we get, 5x(x – 4) + 14 (x – 4) = 0
X = 39, y = – 29 (5x + 14) (x – 4) = 0
x> y X = -14/5, 4 = -2.8, 4
27) Answer: d) II. 6y2 + 9y – 42 = 0
I. 2x2 + 13x + 20 =0 6y2 -12y + 21y – 42 = 0
2x2 + 8x + 5x + 20 =0 6y(y – 2) + 21(y – 2) = 0
2x(x + 4) + 5(x + 4) = 0 (6y + 21) (y – 2) = 0
(2x + 5) (x + 4) = 0 Y = -21/6, 2 = -3.5, 2
X = -5/2, -4 Can’t be determined
II. 3y2 – y – 10 = 0 31) Answer: c)
3y2 – 6y + 5y – 10 = 0 I. 3x2 +14x +15 = 0
3y(y – 2) + 5(y – 2) = 0 3x2 +9x + 5x + 15 = 0
(3y + 5) (y – 2) =0 3x(x+3) + 5(x+3) = 0
Y = -5/2, 2 (3x+5) (x+3) = 0
x≤y X= -5/3, -3
28) Answer: e) II. 3y2 -13y +14 = 0
I. 5x2 + 12x – 9 = 0 3y2 – 6y – 7y +14 = 0
5x2 + 15x – 3x – 9 = 0 3y(y-2)-7 (y-2) = 0
5x(x + 3) -3 (x + 3) = 0 (3y-7)(y – 2) = 0
(5x – 3) (x + 3) = 0 Y= 7/3, 2
X = 3/5, -3 x <y
II. 6y2 – 13y – 8 = 0 32) Answer: e)
6y2 + 3y – 16y – 8 = 0 I. 4x2 – 6x – 18 = 0
3y (2y + 1) -8(2y + 1) = 0 4x2 – 12x + 6x – 18 = 0
(3y – 8) (2y + 1) = 0 4x(x – 3) + 6(x – 3) = 0
Y = 8/3, -1/2 (4x + 6) (x – 3) = 0
Can’t be determined X = -6/4, 3 = -3/2, 3 = -1.5, 3
29) Answer: e) II. 5y2 + 6y – 27 = 0
I. 5x2 + 3x -14 = 0 5y2 + 15y – 9y – 27 = 0
5x2 + 10x – 7x -14 = 0 5y(y + 3) – 9(y + 3) = 0
5x(x + 2) – 7(x+ 2) = 0 (5y – 9)(y + 3) = 0
(5x – 7) (x + 2) = 0 Y = 9/5, -3 = 1.8, -3
X = 7/5, -2 Can’t be determined
II. 5y2 + 8y – 21 = 0 33) Answer: e)
5y2 + 15y – 7y – 21 = 0 I. x2 – 23x + 102 = 0
5y(y + 3) – 7(y + 3) = 0 x2 – 6x – 17y + 102 = 0
(5y – 7) (y + 3) = 0 x(x – 6)- 17(x- 6) = 0
Y = 7/5, -3 (x – 17)(x – 6) = 0
Can’t be determined X = 17, 6
30) Answer: e) II. y2– 24y – 256 = 0

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 TOP 50 Quadratic Equation Questions for Bank PO & Clerk Exams
y2– 32y + 8y – 256 = 0 y2 + 14y + 7y + 98 = 0
y(y – 32) + 8(y – 32) = 0 y(y + 14) + 7(y + 14) = 0
(y + 8) (y – 32) = 0 (y + 7) (y + 14) = 0
Y = -8, 32 Y = -7, -14
Can’t be determined Can’t be determined
34) Answer: c)
5x – 2y = -11-----(1) 39) Answer: a)
3x + 5y = -19------(2)
By solving the equation (1) and (2), we get, I. x2 – 12x – 64 = 0
x = -3, y = -2
x<y x2 + 4x – 16x – 64 = 0
35) Answer: c)
x (x + 4) – 16(x + 4) = 0
I. x = ∜4096
X = 8, -8
(x – 16) (x + 4) = 0
II. y = ∛729
Y=9
X = 16, – 4
x<y
36) Answer: a) II.y2 + 13y + 42 = 0
I. 3x2 – 18x + 27 = 0
3x2 – 9x – 9x + 27 = 0 y2 + 6y + 7y + 42 = 0
3x(x – 3) – 9(x – 3) = 0
(3x – 9) (x – 3) = 0 y (y + 6) + 7(y + 6) = 0
X = 9/3, 3 = 3, 3
II. 5y2 + 11y – 36 = 0 (y + 7) (y + 6) = 0
5y2 + 20y – 9y – 36 = 0
5y(y + 4) – 9 (y + 4) = 0 Y = -7, -6
(5y – 9) (y + 4) = 0 x> y
Y = 9/5, – 4 = 1.8, -4 40) Answer: e)
x> y I. 2x2 + 9x – 45 = 0
37) Answer: a) 2x2 – 6x + 15x – 45 = 0
4x – 5y = 28 -à (1) 2x (x – 3) + 15(x – 3) = 0
3x + 4y = -10 –à (2) (2x + 15) (x – 3) = 0
By solving the equation (1) and (2), X = -15/2, 3 = -7.5, 3
X = 2, y = – 4 II. 4y2 + 19y + 22 = 0
X>y 4y2 + 8y + 11y + 22 = 0
38) Answer: e) 4y(y + 2) + 11(y + 2) = 0
I. x2 + 18x – 115 = 0 (4y + 11) (y + 2) = 0
x2 + 23x – 5x – 115 = 0 Y = -11/4, -2 = -2.75, – 2
x(x + 23) – 5 (x + 23) = 0 Can’t be determined
(x – 5) (x + 23) = 0 41) Answer: e)
X = 5, – 23 I. 7x2 + 27x + 18 = 0
II. y2 + 21y + 98 = 0 7 x2 + 21x + 6x + 18 = 0

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 TOP 50 Quadratic Equation Questions for Bank PO & Clerk Exams
7x(x + 3) + 6(x + 3) = 0 5x(x + 7) – 8(x + 7) = 0
(7x + 6)(x + 3) = 0 (5x – 8) (x + 7) = 0
X = -6/7, -3 = -0.85, -3 X = 8/5, -7 = 1.6, – 7
II. 9y2+ 23y – 12 = 0 II. 7y2 + 11y – 6 = 0
9y2+ 27y – 4y – 12 = 0 7y2 + 14y – 3y – 6 = 0
9y(y + 3) – 4(y + 3) = 0 7y(y + 2) – 3(y + 2) = 0
(9y – 4) (y + 3) = 0 (7y – 3) (y + 2) = 0
Y = 4/9, -3 = 0.44, -3 Y = 3/7, -2 = 0.428, -2
Can’t be determined Can’t be determined
42) Answer: a) 46) Answer: a)
7x – 2y = 25 –à (1) I. x2 – 12x + 36 = 0
5x + 3y = 9 –à (2) (x – 6)(x – 6) = 0
By solving the equation (1) and (2), we get, X = 6, 6
X = 3, y = -2 II. 5y2 + 4y – 12 = 0
x> y 5y2 + 10y – 6y – 12 = 0
43) Answer: e) 5y (y + 2) – 6 (y + 2) = 0
I. 6x2 + 17x – 58 = 0 (5y – 6) (y + 2) = 0
6x2 – 12x + 29x – 58 = 0 Y = 6/5, – 2 = 1.2, -2
6x(x – 2) + 29(x – 2) = 0 x>y
(6x + 29) (x – 2) = 0 47) Answer: c)
X = -29/6, 2 = -4.83, 2 I. 2x2 + 12x + 16 = 0
II. 5y2 – 2y – 72 = 0 2x2 + 4x + 8x + 16 = 0
5y2 – 20y + 18y – 72 = 0 2x(x + 2) + 8(x + 2) = 0
5y(y – 4) + 18(y – 4) = 0 (2x + 8)(x + 2) = 0
(5y + 18) (y – 4) = 0 X = -4, -2
Y = -18/5, 4 = – 3.6, 4 II. 3y2 -7y – 6 = 0
Can’t be determined 3y2 -9y + 2y – 6 = 0
44) Answer: e) 3y(y – 3) + 2(y – 3) = 0
I. 4x2 + 40x + 64 = 0 (3y + 2) (y – 3) = 0
4x2 + 8x + 32x + 64 = 0 Y = – 2/3, 3 = -0.667, 3
4x(x + 2) +32(x + 2) = 0 x<y
(4x + 32) (x + 2) = 0 48) Answer: a)
X = -32/4, -2 = -8, -2 7x + 2y = -13–à (1)
II. 3y2 + 44y + 153 = 0 5x – 4y = 7–à (2)
3y2 + 27y + 17y + 153 = 0 By solving the equation (1) and (2), we get,
3y(y + 9) +17(y + 9) = 0 X = – 1, y = -3
(3y + 17) (y + 9) = 0 x> y
Y = -17/3, -9 = -5.67, -9 49) Answer: e)
Can’t be determined I. x2 + 2x – 15 = 0
45) Answer: e) (x + 5) (x – 3) = 0
I. 5x2 + 27x – 56= 0 X = -5, 3
5x2 + 35x – 8x – 56= 0 II. y2 + y – 56 = 0

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 TOP 50 Quadratic Equation Questions for Bank PO & Clerk Exams
(y + 8) (y – 7) = 0 II. (243)1/5 y + (1728)1/3 = 0
Y = -8, 7 (35)1/5 y = – (123)1/3
Can’t be determined 3y = -12
50) Answer: c) Y = -4
I. √25 x + √5625 = 0 x< y
5x = – 75
X = -15

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