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Activity 2 Remedial.

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Republic of the Philippines

DEPARTMENT OF EDUCATION
Region IV-A CALABARZON
Division of Cavite
TANZA NATIONAL TRADE SCHOOL-ANNEX
Bagtas, Tanza, Cavite

Name:_______________________________________________ Date: ________________

Activity Sheet #2
Remedial Program
Lecture: Laws of Exponent
1. Nth Times. Multiply the base by itself according to the no. of exponent
Ex. 1. 32 = (3)(3) = 9 ; 2. 34 = (3)(3)(3)(3) = 81
2. Power of a Power . Just copy the Literal Coeffecient (variable) and apply the Nth times (if it has
Numerical Coefficient) then multiply the exponents (note. Dapat the same ang variable).
Ex. 1. (x3)3 = x(3)(3) = x9 ; 2. (2w3x4y)2 = 22●w(3)(2)●x(4)(2)●y(1)(2) = 4w6x8y2
3. Product of a Power. Just copy the Literal Coeffecient (variable) and multiply the numerical coofficient
(if it has) then add their exponents (note. Dapat the same ang variable).
Ex. 1. a2 • a4 = a2+4 = a6 ; 2. 4h ● 5i5 = (4●5) ● h ● i5 = 20hi5
4. Quotient of a Power. Just copy the Literal Coeffecient (variable) and Divide the numerical coofficient
(if it has) then Subtract their exponents (note. Dapat the same ang variable).
75x 4 y 6 75 x 4 y 6 2 2 x2
Ex. 1. =    15 x y or15
5x 2 y8 5 x 2 y8 y2
A. Apply the laws of exponents. Simplify.
1. (36x3)
(4x)
2. x3 • x2
3. (x2)3
4. (2a3)5
5. (a22b3)2

Lecture : Addition of Polynomials


Arrange the Given into Column (note. Dapat magkakatapat yung parehas ng Literal coefficient), then
add the numerical coeffivient and copy only the literal cofficient.
Ex.1 5a 3b  4ab 3  11ab  10and  12a 3b  7ab 3  14ab  2 . 2. 18 xy  4 x  9 yand10 x  6 y  5 z
= 5a3b3 - 4ab3 +11ab -10 = 18xy + 4x -9y
-12a3b3 +7ab3 +14ab +2 10x +6y - 5z
= -7a3b3 +3ab3 +25ab - 8 = 18xy + 14x -3y -5z

B. Add the polynomials


1. 4x2y – 3xy2 + 15xy – 12 and -13x2y + 7xy2 +16xy +21
2. 4a – 9b + 12c, 12a + - 9b – 21c, and -5a +6b + 7c
3. 12x4 – 3x2 + 21x – 9 and -29x4 – 34x2 – 17x + 16

Lecture : Subtraction of Polynomials


Arrange the Given into Column (note. Dapat magkakatapat yung parehas ng Literal coefficient), change
the operation into addition ,then change the sign of the subtrahent to its opposite sign. then apply the addition of
polynomial.
Ex. 1. 5a3b3 - 4ab3 +11ab -10 and -12a3b3 +7ab3 +14ab +2 2. 18xy + 4x -9y and 10x +6y - 5z
= 5a3b3 - 4ab3 +11ab -10 = 18xy + 4x -9y
12a3b3 - 7ab3 -14ab - 2 -10x -6y + 5z
= 17a3b3 -11ab3 -3ab - 12 = 18xy - 6x -15y + 5z

C. Subtract the polynomials


1. (38m2 – 27mn +44n2) – (52m2 – 46mn + 59n2)
2. (24p2s2 – 55psr + 81r2) – (-32p2s2 + 65r2)
3. (2x – 23y) – (7x + 5y – 6z)

Lecture : Multiplication of Monomial to Polynomial.


Multiply the monomial by each term of the polynomial.
Ex. 1. 3m (4m3 +3n2) 2. 2ab2 (3a2b2 - 4a3)
= (3m ● 4m3) + (3m ● 3n2) = (2ab2 ● 3a2b2) - (2ab2 ● 4a3)
4 2
= 12m + 9mn = 6a3b4 - 8a4b2
D. Multiply the monomial to the polynomial.
1. 2 (9x − 2y)
2. 10a (a − 3b)
3. 3n (n 2 − 6n + 5)
4. 2k3 (2k2 + k − 4)
5. 7x (x + 2y)

Lecture: Multiplication of Binomial to Binomial


Use FOIL (First term, Outer term, Inner term, Last term) method or Vertical Method
Ex. (5a2 + b2)(-3a + b)
FOIL Method Vertical Method
5a2 + b2
(5a2 + b2)(-3a + b) -3a + b
(5a2 ● -3a)+(b2 ● -3a) = -15a3-3ab2
F = 5a2 ● -3a = -15a3 (5a2 ● b) + ( b2 ● b) = 5a2b + b3

O = 5a ● b = 5a b
2 2 Answer: -15a3 + 5a2b - 3ab2 + b3
I = b ● -3a = -3ab
2 2

L = b2 ● b = b3
Answer : -15a3 + 5a2b - 3ab2 + b3
E. Multiply the following binomials. (Use either F-O-I-L or vertical method.)(4 points)
1. (3y3 + y2 )(−2y2 + y)
2. (m4 + 5m3)(−5m4 + m3)
Lecture : Division of Monomial to Polynomial.
Divide the monomial by each term of the polynomial.
Ex. 75a6b9 + 60 a5b5 +15a2b2 / 15 ab
75a 6b9  60a 5b5  15a 2b 2

15ab
6 9
75a b 60a 5b 5 15a 2b 2
  
15ab 15ab 15ab
= 5a5b8 + 4a4b4 + ab

F. Divide the Monomials to the Polynomials.


1. 45x3y2 + 35x3y / 5x2y
2. 72m5x4y8 + 45m4x3y8 / 9m3x2y4
3. 54x3y3+72x5y6/9x2y2
4. 18 a4b3 + 24 a3b2 / 3 a2b2
5. 39 x3y3 + 66 x3y2 / 3 xy

Lecture: Division of Polynomials by Polynomials.


Steps:
12 x 2
1. Divide the first term of the divisor by the First term of the divident :  2x
6x
2. After getting the quotient, multiply it by the divisor. 2x (6x + 5) = (2x●6x)+(2x●5)= 12x2 + 10x
3. After getting product , subtract it by the divident. 12x2 - 20x
- 12x2 + 10x (follow the rule of
-30 x subtraction of integers)
4. After getting the difference, bring down the next term. Then repeat the steps.

2x - 5
6 x  5 12 x 2  20 x  25
-- 12x2 + 10x
- 30 x - 25
- 30 x - 25
0

G. Divide the Polynomials to the Polynomials. (4 points)


1. 10x2 -17x -20 / 5x + 4.
2. 4x2 + 27x + 18 / x + 6

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