CM Monthly Test - XII - Test 5 - 13.06.2016
CM Monthly Test - XII - Test 5 - 13.06.2016
CM Monthly Test - XII - Test 5 - 13.06.2016
MONTHLY
ASSESSMENT PHYSICS, CHEMISTRY & MATHEMATICS
CM - TEST CODE: 101194
Time Allotted: 3 Hours Maximum Marks: 186
Please read the instructions carefully. You are allotted 5 minutes specifically for
this purpose.
You are not allowed to leave the Examination H all before the end of the test.
INSTRUCTIONS
Caution: Question Paper CODE as given above MUST be correctly marked in the answer OMR
sheet before attempting the paper. Wrong CODE or no CODE will give wrong results.
A. General Instructions
BATCHES – 57
1. Attempt ALL the questions. Answers have to be marked on the OMR sheets.
2. This question paper contains Three Section.
3. Section - I is Physics, Section - II is Chemistry and Section - III is Mathematics.
4. Each section is further divided into two part: Part-A & Part-C
5. Rough spaces are provided for rough work inside the question paper. No additional sheets will be
provided for rough work.
6. Blank Papers, clip boards, log tables, slide rule, calculator, cellular phones, pagers and electronic
devices, in any form, are not allowed.
(ii) Part-A (06 – 13) contains 8 multiple choice questions which have one or more than one correct
answer. Each question carries +4 marks for all correct answer, +1 marks for each correct answer
There is no negative marking.
(iii) Part-C (01 – 05) contains 5 Numerical based questions with single digit integer as answer, ranging
from 0 to 9 and each question carries +3 marks for correct answer. There is no negative marking.
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SECTION I : PHYSICS
PART – A : (Single Correct Answer Type)
This section contains 5 multiple choice questions. Each question has four choices (A), (B), (C) and (D)
out of which ONLY ONE is correct.
1. The arc AB with the centre C and the infinitely long wire having + B
linear charge density are lying in the same plane. The minimum +
+
amount of work to be done to move a point charge q0 from point A +
to B through a circular path AB of radius a is equal to : +
q02 2 q0 3 +
C a A
(A) n (B) n + 2a
20 3 20 2 +
+
q0 2 q0
(C) n
20 3
(D)
20
2. Three large plates are arranged as shown. How much charge will Q 2Q
flow through the key K if it is closed? d 2d
(A) 5Q/6 (B) 4Q/3
(C) 3Q/2 (D) Q/2
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IT-2017-SANKALP - 57-XII-PCM-(0000.0)-4
6V
F
PART – A : (Multiple Correct Answers Type)
This section contains 8 multiple choice questions. Each question has four choices (A), (B), (C) and (D)
out of which ONE OR MORE may be correct.
20 20
2mu2
(D) Velocity of the particle of charge q is changing in magnitude
and direction both
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7. A particle of mass m and charge q is projected in a region where an electric field is existing and
given by E E0 ˆi, with a velocity v 0 ˆj from the origin at time t = 0, then choose the correct
statements (assuming mv 02 2qE0 x0 ).
(A) radius of curvature of the particle when its x-coordinate becomes x0 is 2x0.
(B) radius of curvature of the particle when its x-coordinate becomes x0 is 4 2x0 .
(C) speed of the particle when its x-coordinate becomes x0 is 2v 0 .
(D) speed of the particle when its x-coordinate becomes x0 is 2v0.
8. The electric potential in a region along the x-axis varies with x-according to the relation V(x) = 4 +
2
5x . Then
(A) potential difference between the points x = 1 and x = – 2 is 15V
(B) the force experienced by the above charge will be toward the + x-axis
(C) a uniform electric field exists in this region along the + x-axis
(D) force experienced by a 1C charge at x = – 1 m will be 10N
10. The following figure shows a block of mass m suspended from a fixed point by
means of a vertical spring. The block is oscillating simple harmonically and
carries a charge q. There also exists a uniform electric field in the region.
Consider four different cases. The electric field is zero in case 1, mg/q k
downward in case 2, mg/q upward in case 3, and 2mg/q downward in case 4.
The speed at mean position is same in all cases. Select the correct
alternative(s). m, q
(A) Time periods of oscillation are equal in case 1 and case 3.
(B) Amplitudes of displacement are same in case 2 and case 3.
(C) The maximum elongation (increment in length from natural length) is
maximum in case 4.
(D) Time periods of oscillation are equal in case 2 and case 4.
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11. Each of the following figures shows electric field vectors at two places in an electric field. In which
figure or figures can the illustrated field be created by a single point charge?
(A) (B)
(C) (D)
2 -2 3
12. A parallel plate capacitor of plate area 0.2 m and spacing 10 m is charged to 10 volt and then
disconnected from the battery, and pulled apart to double the plate spacing
(A) work required to pull the plate is 8.8 10 J
-5
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3. The electric field strength depends only on the x, y and z coordinates according to the law
E
a xiˆ yjˆ zkˆ 2 –1
, where a = 280 Nm C is a constant. If the potential difference between (3,
3/ 2
x y z
2 2 2
2
2, 6) and (0, 3, 4) is x . What is the value of x.
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IT-2017-SANKALP - 57-XII-PCM-(0000.0)-8
SECTION II : CHEMISTRY
PART – A : (Single Correct Answer Type)
This section contains 5 multiple choice questions. Each question has four choices (A), (B), (C) and (D)
out of which ONLY ONE is correct.
Br
+ Ph CH 2 NH2 EtO-
1. Product, Product is
Ph
O
Et
Ph
(A) (B) NH Ph
Ph O
O
Br
(C) (D) Ph NH
Ph NH Ph Ph
OH
CH3
2. H3C Cl2 , h
N (isomeric products) C5 H11Cl
fractional distillation
M (isomeric products)
CH3
What are N and M?
(A) 6, 6 (B) 6, 4
(C) 4, 4 (D) 3, 3
3. ClCH2CHCl2
alcoholic
KOH/
X major product
What will be the major product X of the above reaction?
(A) CHCl = CHCl (B) CH2 CCl2
(C) HC CH (D) ClCH2CHO
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IT-2017-SANKALP –57-XII-PCM-(0000.0)-9
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F
PhS Na
dim ethylformamide
NO 2
Me SPh Me SPh
F F
(A) (B)
NO 2 NO 2
Me Br Me SPh
SPh SPh
(C) (D)
NO 2 NO 2
H O OH
X Y
B H THF
2 6 2 2
5.
HO OH HO OH
(A) (B)
OH OH
HO
OH
OH
(C) (D)
OH
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B H
O
2 6
OH, H2 O 2
(A) Syn addition of –H (from BH3) and –OH (from solution) occur
(B) Syn addition of –H (from BH3) and –OH (from H2O2) occur
(C) The product is optically inactive
(D) Addition follows anti-Markownikoff orientation
CH3 O
PBr Mg CH CH C H
7. OH
3
A
Et O
B
3
H /H O
C
2 2
OH CH3
CH3
(C) C is CH CH (D) C is CH 2 C CH3
CH3
OH
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IT-2017-SANKALP –57-XII-PCM-(0000.0)-11
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NO2
F
OCH3
(C) (D)
Br NO 2
H /H O
(B)
2
H /H O
2 2
OH OH
H /H O
(D)
H /H O
2
2 2
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NO 2
OH COOH
NO 2 NO 2
(C) (D)
11. An organic compound (A) with molecular formula C7H14O, when treated with cold HI, gives (B)
+
and (C). (B) on treatment with H in presence of heat produced (D), which on treatment with
Br2/CCl4 gave C5H8Br2. Which of the following can be the structure of (A)?
(C) (D) O
O
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12. The reactivity of compound Z with different halogens under appropriate conditions is given below:
OH mono halo substituted derivative when X 2 I2
X2
di halo substituted derivative when X 2 Br2
C(CH3)3
Z
tri halo substituted derivative when X 2 Cl 2
The observed pattern of electrophilic substitution can be explained by
(A) the steric effect of the halogen
(B) the steric effect of the tert-butyl group
(C) the electronic effect of the phenolic group
(D) the electronic effect of the tert-butyl group
13. Toluene, when treated with Br2/Fe, gives p-bromotoluene as the major product because CH3
group
(A) is para directing (B) is meta directing
(C) activates the ring by hyperconjugation (D) deactivates the ring
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IT-2017-SANKALP - 57-XII-PCM-(0000.0)-14
1. How many sigma bonded oxygen atoms present in the product of following reaction
dil
H SO
Pr oduct
2 4
O O
2. i) LiAlH4
Maleic anhydride
i) O3
ii) H2 O
excess
ii) H O
X
3
3. Total number of final product(s) (including isomers) in the following conversion is/are:
CH 3CH 3
H3C C C CH 3 NaI
CH3 COCH3
A
NBS(1 equivalent )/hv
?
Br Br
OH
O
5. ||
3
Cl C Cl
ii H2O
SOCl2 alc. KOH i CH MgBr
HBr
AlCl3
In the above sequence of reaction how many nucleophilic substitution taking place?
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IT-2017-SANKALP –57-XII-PCM-(0000.0)-15
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1. Number of values of x which are not in the domain of derivative of the function
x 1
3/5
; x 1
f x cos 4x 3x ; 1 x 1 is
1 3
3
x 1 5 ; 1 x 2
(A) 2 (B) 3
(C) 4 (D) 5
Let f(x) be a function defined in [0, 5] such that f (x) = 1 x [0, 5] and f(x) is discontinuous only
2
2.
at all integers in [0, 5], then total number of possible function(s) is(are)
(A) 100 (B) 99
(C) 162 (D) 194
1
Let f : , 1 1, 1 is given by f(x) = 4x – 3x, then f (x) is given by
3 –1
3.
2
1
(A) cos cos1 x
3
(B) 3cos sin1 x
(C) 3sin1 cos x (D) none of these.
4. If an injective function f(x) satisfies the rule f(x) + f(y) + f(xy) = f(x) f(y) + 2 x, y R–{0}. f(1) 1
& f(2) = 9, then the value of f(4) is
(A) 81 (B) 65
(C) 91 (D) 47
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6. f(x) = {sin x} {cos x} is not differentiable at (Note: {k} denotes the fractional part functions of k)
(A) x = 2n (B) x = 2n +
2
(C) x = (2n + 1) (D) x = (2n + 1) +
2
x2 e x2 e
7. If the range of the function f x sin ln 2 cos ln 2 is (a, b] then
x 1 x 1
4 4
(A) a + b = 9 (B) b is an irrational number
a
(C) 1 (D) b is rational number
sin1 cos1
8. Which of the following functions are differentiable x R (Note: [k] and {k} denotes the greatest
integer and fractional part functions of k respectively)
(A) f(x) = |(x – 1)(x – 2)(x – 3)| sin x : x [0, 4]
3 5 7
(B) f(x) = |x – 1| |x – 3/2| |x – 2| |x – 5/2| |x – 3| |x – 7/2| … |x – 100| sin x
x2 x2
(C) f(x) = x 2 ... up to
1 x2
2
1 x2
(D) f(x) = (sin {x}) [x]
3
1 x ; x 1
9. Let f : R R be a function defined as f x and g(x) = f(x – 1) + f(x + 1) x
0 ; x 1
R, then
(A) g(x) is not differentiable at 5 points on R
–1
(B) no of solution of the equation g(x) = cos (cos x) on x [–2, 2] is 3
(C) Range of g(x) is [0, 1]
(D) g(x) is an even function
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10. If f(x) = {x} |sin x| then (Note: [k] and {k} denotes the greatest integer and fractional part
functions of k respectively)
(A) continuous x R (B) not differentiable at integers
(C) L.H.D. at integers is (D) L.H.D. at integers is –
For a certain value of ‘c’ lim x5 7x 4 2 x is finite & non-zero equal to
c
11. , then
x
8 6
(A) c (B) c
5 5
9
(C) 7 (D) c
c 5
4 3
12. Let g(x) = x – 4x + 10. Compress the graph vertically by a factor of 2 followed by a reflection
across the x-axis, we get a function say f(x), then
(A) no of real solution of the equation (f(f(f(x)))) = 0 is 8
(B) no of real solution of the equation (f(f(f(x)))) = 0 is 6
–1
(C) if f : [–1, 3] [ –15/2, 17/2], then f (–5) is 0
17
(D) range of f(x) is ,
2
x 2 x3 x 4 x5 –1
13. Let f(x) = x and let g(x) = f (x), then g(0) is equal to (Note: [k] denotes the
2 3 4 5
greatest integer function less than equal to x)
(A) 1 (B) 0.9
(C) 2 (D) 1.9
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IT-2017-SANKALP - 57-XII-PCM-(0000.0)-18
The number of points in (–, ), for which x – x sin x – cos x = 0 is(are) ____
4 3
1.
x 6000 sin x
6000
K
3. If lim = K, then is equal to ___ (Note: [k] denotes the greatest integer
sin x 500
x 0 2 6000
x
function less than equal to k)
2n 1 x x2 n2 n
1
; n x n
Let f x
2
4. n I, then the number of values of x
1
n 1 x ; n
x n 1
2
where f(x) is not differentiable in (–5, 5) is ‘’ then is ______ (Note: [k] denotes the greatest
3
integer function less than equal to k)
cos x3 ; x0
5. If f x then the number of points where g(x) = f(|x|) is non-
sin x3 x3 1 ; x 0
differentiable is(are)
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PART - A
1. B P121414, P120110
2. A P121424, P120118
3. A P121411, P120108
4. A P121406, P120104
5. C P120118, P121424
PART - A
6. B, C, D P121422
7. B, C P121406, P120104
8. A, D P121408, P120106
9. A, C P121424, P120118
10. A, B, C, D P121406, P120104
11. A, C P121409, P120107
12. A, B P121420, P120114
13. A, B, D P121423, P120117
PART - C
1. 5 P121402, P120101
2. 8 P121422
3. 4 P121408, P120106
4. 3 P121424, P120118
5. 0 P121406, P120104
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IT-2017-SANKALP - 57-XII-PCM-(0000.0)-20
CHEMISTRY (SECTION-II)
PART - A
1. B C124604
2. B C124601
3. B C121802
4. A C124603
5. B C121801
PART - A
6. A, C C121801
7. A, B, C C121802
8. A, B, C, D C124607
9. A, B C121809
10. A, B, D C121809
11. A, B, C C121806
12. A, B, C C124608
13. A, C C124606
PART - C
1. 2 C121807
2. 4 C121804
3. 2 C124601
4. 6 C121801
5. 3 C121808
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IT-2017-SANKALP –57-XII-PCM-(0000.0)-21
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MATHEMATICS (SECTION-III)
PART – A
1. C M120410, M120407
2. C M120308, M120401, M120323
3. A M120311
4. B M120318
5. A M120315
PART – A
6. A, B M120406
7. A, B M120317
8. A, B, C, D M120410, M120407
9. A, B, C, D M120410, M120317, M120320, M120324
10. A, B, D M120410
11. A, B, C M110614
12. A, C, D M120312, M120311, M120317, M120324
13. A, B M120311
PART – C
1. 2 M120325, M120324
2. 7 M120410
3. 2 M110611
4. 6 M120410
5. 2 M120410
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