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Decibel and Noise

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@pinoytsikboy

Decibel

Signals in communication systems span a range of extremely wide magnitude. The
decibel scale, which uses ratios and logarithms, compresses this wide span into smaller,
easier to manipulate range of numbers.

Noise any unwanted, interfering signal is a serious problem with communication
systems. It is often measured in decibels in relation to the desired signal.

Decibel a convenient logarithmic scale to overcome wide range of values in
communication systems. The equation define the dB scale for power

dB = 10 log
O
P
P
1

Where : P
1
and P
o
are power ratios

In voltage ratios,
dB = 10 log
2
2
2
1
V
V

= 20log
2
1
V
V


Note: When using the dB scale with voltage or power, the voltage or current must be
measured at points with the same equivalent resistance.

signal power or voltage are equal, the relative value is 0 dB.
A twice power (P
1
= 2P
o
) , the dB ratio is 3 db.
At half-power (P
1
/P
o
= 0.5), the dB ratio is 3 dB. (Half-power point)
A percentage gain or loss can be expressed in dB.
+ dB = gain
- dB = loss

dB Reference values

dB is the ration of two power or voltage values, not an absolute unit of measurement of
volt or watt. As a result of this shortcoming, several reference values are use in the
industry. This means that all dB values are stated is relative to a given standard value.

Using 1 mW (0.001 W) as reference:

dBm = 10 log
mW
P
1
1
= 10 log
001 . 0
1
P



@pinoytsikboy
Using 1W as reference:

dBW = 10 log
W
P
1
1


Using 1 V as reference:
dBV = 10 log
V
P
1
1


Addition and subtraction of dB:

1. dB dB = dB
total
(direct addition or subtraction)
example:
1. 1 dB + 2 dB = 3 dB (gain)
2. 1 dB 2dB = -1 dB (loss)

2. dB dBm = dBm
total

example:
1. 1 dB + 2 dBm = 3 dBm (gain)
2. 1 dB 2dBm = -1 dBm (loss)

3. dBm dBm = (cannot be added/subtracted directly)
example:
1. 1 dBm + 2 dBm =

1 dBm = 10 log (Po/ 0.001)
Po =(0.001)x log
-1
10
1
= 1.25 mW

2 dBm = 10 log (P1/ 0.001)
P1 =(0.001)x log
-1
10
2
= 1.585 mW

Then add Po and P1 : Pt = 1.25 mW + 1.585 mW = 2.84 mW

Use 1mW as reference: dBm = 10 log
mW
mW
1
84 . 2
= 10 (0.4553) = 4.55 dBm

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