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    Flash Distillation Problem

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    prudhvifire
    A 50 mole% hexane and 50 mole% octane feed is flashed, with 50% of the feed vaporizing. Using equilibrium data and flash calculations, the compositions of the vapor and liquid products are determined to be 69% hexane in the vapor and 31% hexane in the liquid.

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    Flash Distillation Problem

    Uploaded by

    prudhvifire
    249 views2 pages
    A 50 mole% hexane and 50 mole% octane feed is flashed, with 50% of the feed vaporizing. Using equilibrium data and flash calculations, the compositions of the vapor and liquid products are determined to be 69% hexane in the vapor and 31% hexane in the liquid.

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    flash distillation

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    © Attribution Non-Commercial (BY-NC)

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    A 50 mole% hexane and 50 mole% octane feed is flashed, with 50% of the feed vaporizing. Using equilibrium data and flash calculations, the compositions of the vapor and liquid products are determined to be 69% hexane in the vapor and 31% hexane in the liquid.

    Copyright:

    Attribution Non-Commercial (BY-NC)
    Download as DOCX, PDF, TXT or read online from Scribd
    Download as docx, pdf, or txt
    249 views2 pages

    Flash Distillation Problem

    Uploaded by

    prudhvifire
    A 50 mole% hexane and 50 mole% octane feed is flashed, with 50% of the feed vaporizing. Using equilibrium data and flash calculations, the compositions of the vapor and liquid products are determined to be 69% hexane in the vapor and 31% hexane in the liquid.

    Copyright:

    Attribution Non-Commercial (BY-NC)
    Download as DOCX, PDF, TXT or read online from Scribd
    Download as docx, pdf, or txt
    of 2

    A feed of 50 mole % hexane and 50 mole % octane is fed into a pipe still through a pressure reducing valve and

    then into a flash disengaging chamber. The vapor and liquid leaving the chamber are assumed to be in equilibrium. If the fraction of the feed converted to the vapor is 0.5, find the compositions of the top and bottom products. The following table gives the equilibrium data for this system.
    Mole fractions of hexane in liquid x Mole fractions of hexane in vapor y 1.00 1.00 0.69 0.932 0.40 0.78 0.192 0.538 0.045 0.1775 0.00 0.00

    Calculations: Basis: 100 mole of feed F = 100 mol zF = 0.5 D = 100 x 0.5 = 50 mol W = F - D = 50 mol Slope of the operating line = -W/D = -1 With these data, the equilibrium curve and operating line for flash distillation are plotted as follows:

    From the plot, it could be seen that the operating line cuts the equilibrium curve at the point (0.31, 0.69). That is yD = 0.69 and xW = 0.31 Composition of top product = yD = 69% Hexane Composition of bottom product = xW = 31% Hexane

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