OFFSET
0,5
COMMENTS
For n>0, A000105(n) + a(n) = A000988(n) because the number of free polyominoes plus the number of polyominoes lacking bilateral symmetry equals the number of one-sided polyominoes. - Graeme McRae, Jan 05 2006
For n>0, each chiral pair is counted as one. - Robert A. Russell, Feb 23 2022
LINKS
John Mason, Table of n, a(n) for n = 0..50 (terms 1..45 from Andrew Howroyd, 46..48 from Robert A. Russell)
D. H. Redelmeier, Counting polyominoes: yet another attack, Discrete Math., 36 (1981), 191-203.
FORMULA
EXAMPLE
For a(4)=2, the two chiral tetrominoes are XXX and XX .
X XX
MATHEMATICA
Array[a, 45] (* Jean-François Alcover, Sep 08 2019, after Graeme McRae *)
CROSSREFS
KEYWORD
nonn
AUTHOR
EXTENSIONS
Terms a(23) and beyond from Andrew Howroyd, Dec 04 2018
Name edited by Robert A. Russell, Feb 03 2019
a(0)=0 corrected by John Mason, Jan 12 2023
STATUS
approved