So, I've found the exact (enough) items in the pit.
The paws are 2.8 in by 2.2 in, I gave a depth of like idk, 1, so 6.16 in^3.
The crabs are exactly 2.1 in by 1.4 in by 0.4 in giving about 1.15 in^3
The horses are 2 in by 1.5 ish in, by 0.4 in estimated from the exact measurement found for the crab and the similar thickness. So roughly 1.2 in^3.
There's also the banana. The average volume of a banana is about 6.71 in^3, so we can subtract this from the total volume of the ball pit.
Now, this is a small ball pit. And thankfully we have the measurements.
Except, the ball pit isn't fully like, full.
And, it's inside out. So, the diameter will be closer to 31 because the seams are all... Weird. I think. I mean it sure looks inside out, and the margin for error here is p big.
So, really the volume is with a height of ~3 (based on an estimate from the paw layering of one fully upright and one on its side) and a good middle of the road diameter of 31 giving us around 2,264.19 in^3.
Minus 6.71 in^3 so 2,257.48 in^3.
The issue now is that there are in fact all 3 of these things, and the banana but the banana is now negligible. (Maybe. Not a ball pit distribution scientist or anything.)
Now based on the options given assuming they're not all wrong, we can figure out roughly how much of each could be in here from the values we have.
So! Let's do this in the, probably, most convoluted way possible then, shall we? Because I'm terrible at math, but I can make a flowchart!
Through use of a flow chart, there are 5 possible answers.
For Crabs, it will never be 278, since none of those sums give us an answer option for the total.
For Horses, it will never be 256.
For Paws, it will never be 231.
The possible paths are as follows:
Just looking at it with common sense and knowledge of probabilities, you could make a good educated guess, but, I've come to far to be wrong.
Honestly it's probably all still wrong, I'm not smart.
But, we now only have one real based on volume calculations. E. Which yk, not the logical choice if you just guestimate from the 5 possible based on common numbers between routes. But with E, you get like, 2,191 in^3. I think. The calculator could be a liar though for all I know.
I won't lie I'm not confident in this but uh, I got an answer that's preeeeetty close. I also had to estimate some measurements of the paws and the horses since there were no like, listed numbers. Also the crabs are assorted and there's def crawfish/lobsters in there too that are sliiiightly bigger.
So, close enough! Uh, if you want like, links, for the stuff I got em. Everything came from Big Daddy Bezos so you can just look it up lmao. I realized bcs I considered buying a pack of those crabs off Amazon before for sillies.