Nothing Special   »   [go: up one dir, main page]

×
Please click here if you are not redirected within a few seconds.
For any finite sequence of positive numbers ( 𝑎 𝑗 ) 𝑛 𝑗 = 1 whose partial sums are ( 𝑆 𝑗 ) 𝑛 𝑗 = 1 and for all integers 𝑘 ≥ 1 we have 𝑛 ∑ 𝑗 = 1 𝑘 ∑ 𝑚 = 1 ( 𝑘 𝑚 ) ...
May 10, 2019 · kth Power of a Partial Sum. Angel Plaza. To cite this article: Angel Plaza (2019) kth Power of a Partial Sum, The American Mathematical.
Abstract. A recurrence formula for the k th Power of a Partial Sum is deduced and applied in some examples.
Nov 4, 2014 · 2) From the finite difference considerations it is clear that the formula for the sum of the k-th powers is a polinomial of degree k+1 in n.
In this paper, we give a generalization of Ibn al-Haytham recursive formula for sums of powers of any integer sequence. Then, we obtain higher dimensional ...
Here we prove the following extension of the previous result. Theorem 2. For any finite sequence of positive numbers aj n j=1 whose partial sums.
Title: kth power of a partial sum ; Authors: Plaza, Angel ; UNESCO Clasification: 120222 Series, sumabilidad ; Issue Date: 2019 ; Journal: The American mathematical ...
Euler's sum of powers conjecture (disproved) concerns situations in which the sum of n integers, each a kth power of an integer, equals another kth power.
Apr 13, 2018 · It turns out that the sum of the Mth M th power of the first N N natural numbers is given by a polynomial of degree M+1 M + 1 . Here's a ...
People also ask