We prove that, for any positive integer m, a segment may be partitioned into m possibly degenerate or empty segments with equal values of a continuous function f evaluated on segments, assuming that f may take positive and negative values, but its value on degenerate or empty segments is zero.
Mar 22, 2022
Sep 18, 2020 · We prove that, for any positive integer m, a segment may be partitioned into m possibly degenerate or empty segments with equal values of a continuous function ...
We prove that, for any positive integer $m$, a segment may be partitioned into $m$ possibly degenerate or empty segments with equal values of a continuous ...
We prove that, for any positive integer m, a segment may be partitioned into m possibly degenerate or empty segments with equal values of a continuous function ...
If the segment [a,b] is degenerate, a b, then we think of all such partitions as the partition of the degenerate segment into degenerate segments. But we still ...
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We prove that, for any positive integer m , a segment may be partitioned into m possibly degenerate or empty segments with equal values of a continuous ...
Sep 10, 2024 · We prove that, for any positive integer $m$, a segment may be partitioned into $m$ possibly degenerate or empty segments with equal values ...
Dec 5, 2019 · The equipartition theorem requires that each degree of freedom that appears only quadratically in the total energy has an average energy of ½kBT ...
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In classical statistical mechanics, the equipartition theorem relates the temperature of a system to its average energies.
A result from classical statistical mechanics is the equipartition theorem: When a substance is in equilibrium, there is an average energy of kT/2 per molecule ...