Talk:Solar irradiance: Difference between revisions

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The first sentence of the article says "Solar irradiance (also Insolation, from Latin insolare, to expose to the sun)[1][2] is the power per unit area produced by the Sun in the form of electromagnetic radiation" but the units stated further along are MJ/m². There are also many ambiguous units like kWh/m²/day and such. I think the units should all be power/area as in the definition. Chthonicdaemon (talk) 04:30, 28 September 2015 (UTC)[reply]

I wonder how could be calculated 24 h/day on a single plot of land without refer to night (no sun),365 days/year also without any respect to season(winter full of cloud) it's misleading information detract logic ,also there are other attributes like longitude and latitude, altitude , efficiency of recovery system to workable load .@Arch dude, Puduḫepa, HasteurBot, Dan arndt, ~riley, RudolfRed, and Eric:Winghovercraft (talk) 22:05, 14 February 2020 (UTC)Winghovercraft[reply]

https://www.pveducation.org/pvcdrom/properties-of-sunlight/calculation-of-solar-insolation

https://meteoexploration.com/products/SolarCalculator.html

https://sciencing.com/calculate-solar-insolation-8435082.html

https://sciencing.com/solar-altitude-23364.html

https://sciencing.com/what-is-the-hottest-time-of-the-day-12572821.html

https://www.efficientenergysaving.co.uk/solar-irradiance-calculator.html

http://www.solarelectricityhandbook.com/ @DLH, Damorbel, Scottprovost, O-Jay, SilverbackNet, and 2A02:168:F609:0:D894:A6AA:493E:8587: Winghovercraft (talk) 22:20, 14 February 2020 (UTC)Winghovercraft[reply]

No precise calculation especially outer space of Earth or on it's surface . Winghovercraft (talk) 22:38, 14 February 2020 (UTC)Winghovercraft[reply]

Doesn't the magnetosphere interfere with "solar radiation"? Shouldnt the subtractions from space insolation include Earth magnetosphere caused reductions? Didnt see magnetosphere in intro paragraph of this topic. Or did i miss something? Thanks to all. Mike H. mlhootenoutlook

The table under Solar_irradiance#Applications is confusing at best and possibly profoundly erroneous. In general you cannot convert between power and energy without knowing time. In this table (pasted to the side), it appears the assumption is 24 hours per day of full sun, which is not true for any spot on earth. I suggest that we delete the entire table.

I would love to hear your thoughts.

--Lonny (LRG) (talk) 21:52, 9 April 2020 (UTC)[reply]

The table is correct. All quantities are (or are equivalent to) power per unit area. In the case of sun-hour/day, a sun-hour is defined as one hour of 1kW/m^2 irradiation per day = 1kWh/(m^2 day). In the case of kWh/(kWp year), it is equivalent to a measure of the average irradiance during a year. --Ita140188 (talk) 03:15, 10 April 2020 (UTC)[reply]

I am not sure about how useful it is though. These quantities can be compared in terms of units, but they represent very different things, so a conversion table is not that useful in my opinion, and may be misleading. So personally I am ok with removing it. --Ita140188 (talk) 03:18, 10 April 2020 (UTC)[reply]