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Optimization with Demand Oracles

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Abstract

We study maximization subject to a budget constraint, where we are given a valuation function v, budget B and a cost \(c_i\) for each item i. The goal is to find a set S that maximizes v(S) subject to \(\Sigma _{i\in S}c_i\le B\). Special cases of this problem are well-studied problems from submodular optimization. In particular, when the costs are all equal (cardinality constraint), a classic result by Nemhauser et al. shows that the greedy algorithm provides an \(\frac{e}{e-1}\) approximation. Motivated by a large body of literature that utilizes demand queries to elicit the preferences of agents in economic settings, we develop algorithms that guarantee improved approximation ratios in the presence of demand oracles. We are able to break the \(\frac{e}{e-1}\) barrier: we present algorithms that use only polynomially many demand queries and have approximation ratios of \(\frac{9}{8}+\epsilon \) for the general problem and \(\frac{9}{8}\) for maximization subject to a cardinality constraint. We also consider the more general class of subadditive valuations. Here, if the valuations can only be accessed by value queries, only trivial approximation ratios can be guaranteed. In contrast, we present algorithms that use demand queries and obtain an approximation ratio of \(2+\epsilon \) for the general problem and 2 for maximization subject to a cardinality constraint. We guarantee these approximation ratios even when the valuations are non-monotone. We show that these ratios are essentially optimal, in the sense that for any constant \(\epsilon >0\), obtaining an approximation ratio of \(2-\epsilon \) requires exponentially many demand queries.

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Notes

  1. This bound holds even if the valuation is fractionally subadditive—a valuation is fractionally subadditive (a.k.a. XOS) if it is the maximum of several additive valuations. A formal definition will be presented later.

  2. This first step is very similar to the use of demand oracles in algorithms for combinatorial auctions, where demand oracles are used to solve the LP [10, 14, 15], but the similarity between the algorithms ends here.

  3. Simultaneously and independently, a constant-factor algorithm for this problem was also obtained in [4], but with a worse approximation factor. Their algorithm can be seen as a more subtle variant of the logarithmic approximation of [12] and is not based on LP rounding, as ours.

  4. The most relevant lower bound that applies specifically to demand queries is that of Nisan and Segal [26]. However, the setting of [26] is much simpler, and their ideas do not seem to be applicable in our case.

  5. We also consider some generalizations, which will be defined in the proper subsections.

  6. Of course, to obtain a discrete process one may increment \(\lambda \) in some discrete amount. This results in some loss in the approximation ratios of the algorithms that we construct (the loss depends on the size of the increments).

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Acknowledgements

We thank Bobby Kleinberg for helpful discussions.

Funding

Funding was provided by Israel Science Foundation.

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Correspondence to Shahar Dobzinski.

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A preliminary version of this paper appeared in EC’12.

Appendix for Section 4

Appendix for Section 4

1.1 Proof of Claim 4.5

The proof is basically an algebraic manipulation:

$$\begin{aligned} \gamma= & {} \underset{k_1\le k\le k_2}{\max } \alpha \cdot \frac{k_2}{k_1+k_2-k}+ \left( (1-\alpha )-\alpha \cdot \frac{k-k_1}{k_1+k_2-k}\right) \frac{k_2}{k} \nonumber \\= & {} \underset{k_1\le k\le k_2}{\max } \frac{k_2-k}{k_2-k_1}\cdot \frac{k_2}{k_1+k_2-k} +\left( \frac{k-k_1}{k_2-k_1}-\frac{k_2-k}{k_2-k_1}\cdot \frac{k-k_1}{k_1+k_2-k}\right) \frac{k_2}{k} \nonumber \\= & {} \underset{k_1\le k\le k_2}{\max } \frac{k_2-k}{k_2-k_1}\cdot \frac{k_2}{k_1+k_2-k} \cdot \left( 1-\frac{k-k_1}{k}\right) +\frac{k-k_1}{k_2-k_1}\cdot \frac{k_2}{k} \nonumber \\= & {} \underset{k_1\le k\le k_2}{\max } \frac{k_2-k}{k_2-k_1}\cdot \frac{k_2}{k_1+k_2-k} \cdot \frac{k_1}{k}+\frac{k-k_1}{k_2-k_1}\cdot \frac{k_2}{k}\nonumber \\= & {} \underset{k_1\le k\le k_2}{\max } \frac{k_2}{k(k_2-k_1)}\cdot \frac{k(k_1+k_2)-k^2-k_1^2}{k_1+k_2-k} \nonumber \\= & {} \underset{k_1\le k\le k_2}{\max } \frac{k_2}{(k_2-k_1)}\cdot \left( 1-\frac{k_1^2}{k(k_1+k_2-k)}\right) \nonumber \\= & {} \underset{k_1\le k_2}{\max } \frac{k_2}{(k_2-k_1)}\cdot \left( 1-\frac{4k_1^2}{(k_1+k_2)^2}\right) \nonumber \\= & {} \underset{k_1\le k_2}{\max } \frac{k_2}{(k_2-k_1)}\cdot \frac{k_2^2+2k_1k_2-3k_1^2}{(k_1+k_2)^2} \nonumber \\= & {} \underset{k_1\le k_2}{\max } \frac{k_2}{(k_2-k_1)}\cdot \frac{(k_2+3k_1)\cdot (k_2-k_1)}{(k_1+k_2)^2} \nonumber \\= & {} \underset{k_1\le k_2}{\max } \frac{(k_2+3k_1)\cdot k_2}{(k_1+k_2)^2} \nonumber \\= & {} \underset{x\ge 1}{\max } \frac{(x+3)\cdot x}{(x+1)^2} \nonumber \\= & {} \frac{9}{8} \end{aligned}$$
(5)

where in (5) we use the fact that the expression is maximized at \(k=\frac{k_1+k_2}{2}\). In the second to last equation we set \(x=\frac{k_2}{k_1}\).

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Badanidiyuru, A., Dobzinski, S. & Oren, S. Optimization with Demand Oracles. Algorithmica 81, 2244–2269 (2019). https://doi.org/10.1007/s00453-018-00532-x

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