ON THE EXISTENCE OF AN INVARIANT NON-DEGENERATE BILINEAR
FORM UNDER A LINEAR MAP
arXiv:0903.0826v3 [math.AC] 7 Jun 2010
KRISHNENDU GONGOPADHYAY AND RAVI S. KULKARNI
Abstract. Let V be a vector space over a field F. Assume that the characteristic of F is large, i.e.
char(F) > dim V. Let T : V → V be an invertible linear map. We answer the following question in this
paper. When does V admit a T -invariant non-degenerate symmetric (resp. skew-symmetric) bilinear
form? We also answer the infinitesimal version of this question.
Following Feit-Zuckerman [2], an element g in a group G is called real if it is conjugate in G to its
own inverse. So it is important to characterize real elements in GL(V, F). As a consequence of the
answers to the above question, we offer a characterization of the real elements in GL(V, F).
Suppose V is equipped with a non-degenerate symmetric (resp. skew-symmetric) bilinear form
B. Let S be an element in the isometry group I(V, B). A non-degenerate S-invariant subspace W
of (V, B) is called orthogonally indecomposable with respect to S if it is not an orthogonal sum of
proper S-invariant subspaces. We classify the orthogonally indecomposable subspaces. This problem
is nontrivial for the unipotent elements in I(V, B). The level of a unipotent T is the least integer k
such that (T − I)k = 0. We also classify the levels of unipotents in I(V, B).
1. Introduction
Let F be a field, and let F̄ denote its algebraic closure. Let V be a vector space of dimension n over
F. The group of all invertible linear maps from V to V is denoted by GL(V, F), or simply by GL(V)
when there is no confusion about the field F. In this paper we ask the following question.
Question 1. Given an invertible linear map T : V → V, when does the vector space V admit a
T -invariant non-degenerate symmetric (resp. skew-symmetric) bilinear form?
Assuming that the characteristic of F is large, i.e. char(F) > dim V, we have answered the question
in this paper.
Let f (x) be a monic polynomial of degree d over F such that −1, 0, 1 are not its roots. The dual
of f (x) is defined to be the polynomial f ∗ (x) = f (0)−1 xd f (x−1 ). Note that if f (x) = Σdi=1 ai xi , then
f ∗ (x) = a10 Σdi=0 ad−i xi . In other words, if α in F̄ is a root of f (x) with multiplicity k, then α−1 is a
root of f ∗ (x) with the same multiplicity. The polynomial f (x) is said to be self-dual if f (x) = f ∗ (x).
Note that if f is self-dual, then a0 = 1.
Let T : V → V be a linear transformation. A T -invariant subspace is said to be indecomposable
with respect to T , or simply T -indecomposable if it can not be expressed as a direct sum of two
proper T -invariant subspaces. Clearly V can be written as a direct sum V = Σm
i=1 Vi , where each Vi is
T -indecomposable for i = 1, 2, ..., m. In general, this decomposition is not canonical. But for each i,
(Vi , T |Vi ) is “dynamically equivalent” to (F[x]/((p(x)k ), µx ), where p(x) is an irreducible monic factor
Date: June 7, 2010.
2000 Mathematics Subject Classification. Primary 15A63; Secondary 15A04, 20E45, 20G05.
Key words and phrases. linear map, bilinear form, unipotents, real elements.
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KRISHNENDU GONGOPADHYAY AND RAVI S. KULKARNI
of the minimal polynomial of T , and µx is the operator [u(x)] 7→ [xu(x)]. Such p(x)k is an elementary
divisor of T . If p(x)k occurs d times in the decomposition, we call d the multiplicity of the elementary
divisor p(x)k . By the theory of rational canonical form of linear maps, elementary divisors, counted
with multiplicities, determine (V, T ) upto “dynamic equivalence”, cf. Kulkarni [5] for the dynamical
viewpoint.
Let χT (x) denote the characteristic polynomial of an invertible linear map T . Let
χT (x) = (x − 1)e (x + 1)f χoT (x),
where e, f ≥ 0, and χoT (x) has no roots 1, or −1. The polynomial χoT (x) is defined to be the reduced
characteristic polynomial of T . The vector space V has a T -invariant decomposition V = V1 +V−1 +Vo ,
where for λ = 1, −1, Vλ is the generalized eigenspace to λ, i.e.
Vλ = {v ∈ V | (T − λI)n v = 0},
and T |Vo does not have any eigenvalue 1 or -1. Let To denote the restriction of T to Vo . Clearly To
has the characteristic polynomial χoT (x).
Theorem 1.1. Let V be a vector space of dimension n ≥ 2 over a field F of large characteristic.
Let T : V → V be an invertible linear map. Then V admits a T -invariant non-degenerate symmetric
bilinear form if and only if the following conditions hold.
(i) An elementary divisor of To is either self-dual, or its dual is also an elementary divisor with the
same multiplicity.
(ii) Let (x − 1)k , resp. (x + 1)k , be an elementary divisor of T . Then either k is odd or, if k is even,
then the multiplicity of the elementary divisor is an even number. So 2k ≤ n. (If k is odd, then k ≤ n).
Theorem 1.2. Let V be a vector space of dimension 2m ≥ 2 over a field F of large characteristic. Let
T : V → V be an invertible linear map. Then V admits a T -invariant non-degenerate skew-symmetric
bilinear form if and only if the following conditions hold.
(i) An elementary divisor of To is either self-dual, or its dual is also an elementary divisor with the
same multiplicity.
(ii) Let (x− 1)k , resp. (x+ 1)k , be an elementary divisor of T . Then, either k is even or, if k is odd,
then the multiplicity of the elementary divisor is an even number. So k ≤ m. (If k is even, then k ≤
2m).
When T admits an invariant symmetric, resp. skew-symmetric bilinear form, then Part (i) of the
above theorems are implicit in the work on the conjugacy classes in orthogonal and symplectic groups,
cf. Milnor [6], Springer-Steinberg [9], Wall [13]. Part (ii) of the theorems can be deduced from the
work of Hesselink, cf. [4, section-3] but is not explicitly stated there. The converse parts of the
theorems are the really new contributions of our work. However, for completeness, we shall prove
both parts in this paper, cf. section 4. As we shall see, the converse parts, i.e. the existence of
invariant forms under conditions (i) and (ii), require a subtle understanding of the arithmatic of field
extensions and a detailed analysis of the unipotents.
The analysis of the unipotents are mostly untouched in the work of Milnor [6], Springer-Steinberg
[9] or Wall [13]. Hesselink assumed the ground field to be “quadratically closed” while dealing with
the unipotents. While analyzing the unipotents, the connection with the Jacobson-Morozov lemma
provides the required insight to our work, cf. Gongopadhyay [3]. For the convenience of the reader, we
EXISTANCE OF INVARIANT NON-DEGENERATE BILINEAR FORM UNDER A LINEAR MAP
3
provide here an ab initio complete treatment of this issue. Notice that sl(2, F) admits a unique irreducible representation in each dimension, and further, this representation admits a unique symmetric
(resp. skew-symmetric) invariant form according as the dimension is odd or even. In the terminology
of physics, the so-called “creation”- and “annihilation”-operators are unipotent elements, exemplifying
the terminal cases in the parts (ii) in the above theorems. On the other hand, an arbitrary unipotent
element in the orthogonal or symplectic Lie algebra over an arbitrary field of large characheristic, by
the Jacobson-Morozov lemma is contained in some sub-algebra isomorphic to sl(2, F). This observation has motivated our precise formulation of Theorem 1.1 and Theorem 1.2. Conversely, one could ask
for an “elementary” proof of the Jacobson-Morosov lemma based on Theorem 1.1 and Theorem 1.2.
We hope to see such proof in the near future.
Classification of real elements in the general linear group. Following Feit-Zuckerman [2], an element g
in a group G is said to be real, if it is conjugate in G to its own inverse. If every element in the group
G is real, then G is said to be real. Reality properties of elements in linear algebraic groups are a topic
of research interest due to their connection with the representation theory cf. Feit-Zuckerman [2],
Moeglin et. al. [7], Singh-Thakur [10, 11], Tiep-Zalesski [12]. It is an important problem to classify
real elements in a group G. Wonenburger [14] offered a characterization of real elements in GL(n, F)
as a product of two involutions. As a corollary to Theorem 1.1 and Theorem 1.2, in the following we
give a different criterion which classify real elements in GL(n, F). The corollary follows from the fact
that if T in GL(n, F) is real, then the characteristic polynomial χT (x) is self-dual.
Corollary 1. Let F be a field of large characteristic. Let T be a real element in GL(n, F). Then
V can be decomposed into a direct sum of T -invariant subspaces, V = V1 + V2 , such that V1 admits
a T -invariant non-degenerate symmetric form and V2 admits a T -invariant non-degenerate skewsymmetric form. More precisely,
(i) If T has no eigenvalue +1 or −1, then T preserves a non-degenerate symmetric, as well as a
skew-symmetric bilinear form.
(ii) Let χT (x) = (x − 1)n , resp. (x + 1)n . If all the elementary divisors of T are of even multiplicity,
then it preserves a non-degenerate symmetric, as well as a skew-symmetric bilinear form. If all the
elementary divisors are of odd multiplicity, then T admits an invariant non-degenerate symmetric
bilinear form and it can not admit any non-degenerate skew-symmetric form.
If some of the elementary divisors are of even multiplicity and some are of odd multiplicity, then
there is a direct sum decomposition V = V1 + V2 into T -invariant subspaces such that V1 admits
a T -invariant non-degenerate symmetric form and V2 admits a T -invariant non-degenerate skewsymmetric form.
We prove these theorems in section 4. The existance of the invariant form under a unipotent map
relies on a classification of the T -orthogonally indecomposable subspaces.
Orthogonally indecomposable subspaces under unipotents. Let V be equipped with a non-degenerate
symmetric or skew-symmetric bilinear form B. The group of isometries of (V, B) is denoted by
I(V, B). It is a linear algebraic group. When B is symmetric, resp. skew-symmetric, (V, B) is called
a quadratic, resp. symplectic space. The group of isometries is denoted by O(V, B), resp. Sp(V, B).
They are called the orthogonal and the symplectic groups respectively. A quadratic (resp. symplectic)
space (V, b) is said to be a standard quadratic (resp. symplectic) space if dim V = 2m, and there exists
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KRISHNENDU GONGOPADHYAY AND RAVI S. KULKARNI
subspaces W1 and W2 such that V = W1 + W2 , dim W1 = dim W2 and b|W1 = 0 = b|W2 . Here W1 and
W2 are not unique, but (V, b) is unique upto isometry. The form b is called a standard symmetric,
resp. skew-symmetric form.
Let W be a non-degenerate T -invariant subspace of a quadratic (resp. symplectic) space. Then W
is said to be orthogonally indecomposable with respect to an isometry T if it is not an orthogonal sum
of proper T -invariant subspaces. We classify the orthogonally indecomposable subspaces with respect
to the unipotent isometries or their negatives.
Theorem 1.3. Let (V, B) be a non-degenerate quadratic space over a field F of characteristic different
from 2. Let T : V → V be an isometry with minimal polynomial either (x − 1)k , or (x + 1)k . Let W be
an orthogonally indecomposable subspace with respect to T . Then W has one of the following types.
(i) W is odd dimensional indecomposable.
(ii) W is a standard space and each summand is indecomposable.
Theorem 1.4. Let (V, B) be a non-degenerate symplectic space over a field F of characteristic different
from 2. Let T : V → V be an isometry with minimal polynomial either (x − 1)k , or (x + 1)k . Let W be
an orthogonally indecomposable subspace with respect to T . Then W has one of the following types.
(i) W is even dimensional indecomposable.
(ii) W is a standard space and each summand is indecomposable.
Note that in the case (i) of the above theorems, W is almost ‘standard’ except for an one-dimensional
summand!
Remark 1.5. The tools we have used to derive Theorem 1.1—Theorem 1.4 are simple and linear
algebraic. However, in the large characteristics, Theorem 1.3 and Theorem 1.4 can also be derived by
a notable application of the Jacobson-Morozov lemma. For the statement of the Jascobson-Morozov
lemma cf. Bruhat [1]. In fact, our first proof of these theorems was based on the Jacobson-Morozov
lemma. The condition large characteristic on the base field implies the following.
(a) For each self-dual elementary divisor p(x) of To , p′ (x) 6= 0. Consequently To has the JordanWedderburn-Chevally decomposition, cf. Kulkarni [5, Theorem-5.5].
(b) When T is unipotent, the Jacobson-Morozov lemma holds for T , cf. Bruhat [1].
These are crucial ingredients in the derivation of the main theorems. Condition (a) is necessary
for the proofs. The Jacobson-Morozov lemma provides a sophisticated analysis for the unipotents,
cf. Gongopadhyay [3] when the field is algebraically closed. However, the unipotents can also be
analyzed without using the Jacobson-Morozov lemma. We present a simple linear algebraic approach
to analyse them. This approach is much simpler than the previous attempts, cf. for example, Hesselink
[4]. Moreover, it is valid over any field of characteristic different from 2.
Level of unipotents in orthogonal and symplectic groups. Recall that the level of a unipotent T in a
linear algebraic group is the least integer k for which (T − I)k = 0. The levels unipotents in a linear
representation of a linear algebraic group G is an important invariant of the representation.
Theorem 1.6. Let (V, Q) be a non-degenerate quadratic space of dimension ≥ 3 over a field F of
characteristic different from 2. Let the maximal dimension of a subspace on which Q = 0 is l. Let k
be the level of a unipotent isometry. Then k will be one of the following.
either (a) k ≤ l,
EXISTANCE OF INVARIANT NON-DEGENERATE BILINEAR FORM UNDER A LINEAR MAP
5
or (b) if k > l and dimension of V is 2l, then k is odd and k ≤ 2l − 1.
or (c) if k > l and dimension of V is ≥ 2l + 1, then k is odd and k ≤ 2l + 1.
Theorem 1.7. Let (V, Q) be a non-degenerate symplectic space over a field F of characteristic different
from 2. Let the maximal dimension of a subspace on which Q = 0 is l. Let k be the level of a unipotent
isometry. Then k will be one of the following.
either (a) k ≤ l,
or (b) if k > l and dimension of V is ≥ 2l, then k is even and k ≤ 2l.
Infinitesimal version of Question 1. Further we ask the ‘infinitesimal’ version of Question 1. A bilinear
form b is said to be infinitesimally invariant under a linear map S : V → V, or simply infinitesinally
S-invariant if for all x, y in V,
B(Sx, y) + B(x, Sy) = 0.
The linear maps which preserve B infinitesimally form an abelian group under addition, and this
group is denoted by I(V, B). In fact, I(V, B) is the Lie algebra of the algebraic group I(V, B).
Let f (x) be any monic polynomial of degree d over F such that f (0) 6= 0. Let f − (x) = (−1)d f (−x).
Then f − (x) is called the additive dual polynomial to f (x). A monic polynomial f (x) is called additively
self-dual if f (x) = f (−x). Let p(x) be an elementary divisor of S. If p(x) is not a power of x, we call
it a non-trivial elementary divisor of S.
Theorem 1.8. Let V be a vector space of dimension n ≥ 2 over a field F of large characteristic. Let
S : V → V be a linear map. Then V admits an infinitesimally S-invariant non-degenerate symmetric
bilinear form if and only if the following conditions hold.
(i) A non-trivial elementary divisor of S is either additively self-dual, or its additive dual is also an
elementary divisor with the same multiplicity.
(ii) If xk is an elementary divisor of S and k is even, then the multiplicity of the elementary divisor
is an even number. So k ≤ n. (If k is odd, then k ≤ n).
Theorem 1.9. Let V be a vector space of dimension 2m over a field F of large characteristic. Let
S : V → V be a linear map. Then V admits an infinitesimally S-invariant non-degenerate skewsymmetric bilinear form if and only if the following conditions hold.
(i) A non-trivial elementary divisor of S is either additively self-dual, or its additive dual is also an
elementary divisor with the same multiplicity.
(ii) If xk is an elementary divisor of S and k is odd, then the multiplicity of the elementary divisor
is an even number. So k ≤ m. (If k is even, then k ≤ 2m).
The proofs of the above theorems are analogous to the proof of Theorem 1.1 and Theorem 1.2. We
omit the proofs.
2. Preliminaries
2.1. The Standard Form. Let W be a vector space over a field F. Let W∗ be the dual space to W.
There is a canonical pairing β : W∗ × W → F given by
for w∗ ∈ W∗ , v ∈ W, β(w∗ , v) = w∗ (v).
Moreover β is non-degenerate, i.e. for each w∗ in W∗ , there is a v in W such that β(w∗ , v) 6= 0, and
for each v in W, there exists w∗ in W∗ such that β(w∗ , v) 6= 0.
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KRISHNENDU GONGOPADHYAY AND RAVI S. KULKARNI
For T in GL(W) and v ∈ W, w∗ ∈ W∗ , define (T • w∗ )(v) = w∗ (T −1 v). This defines an action of
GL(W) on W∗ from the left. Further we have
β(T • w∗ , T v) = (T • w∗ )(T v) = w∗ (T −1 T v) = w∗ (v) = β(w∗ , v).
In this sense T preserves the pairing β.
Now consider the vector space
V = W∗ + W.
The pairing β : W∗ × W → F can be extended canonically to a symmetric (resp. symplectic) form b
on V defined as follows.
(i) For w ∈ W, b(w, w) = 0,
(ii) For w∗ ∈ W∗ , b(w∗ , w∗ ) = 0,
(iii) For w∗ ∈ W∗ and v ∈ W, b(w∗ , v) = w∗ (v) = b(v, w∗ ), (resp. −b(v, w∗ ) ). Since β is nondegenerate, we see that b is a non-degenerate symmetric (resp. skew-symmetric) form. Moreover every
invertible linear transformation T : W → W gives rise to an isometry as follows.
Proposition 2.1. There is a canonical embedding of GL(W) into I(V, b).
Proof. Let T : W → W be an invertible linear map. Define the linear map hT : V → V as follows
(
Tu
if u ∈ W
hT (u) =
T • u if u ∈ W∗
Now observe that for v ∈ W, w∗ ∈ W∗ ,
b(hT w∗ , hT v) = (hT w∗ )(hT v) = (T • w∗ )(T v) = w∗ (T −1 T v) = w∗ (v) = b(w∗ , v).
This shows that hT is an isometry. The correspondence T 7→ hT gives the desired
embedding.
Let End(W) denote the Lie algebra over F of all linear endomorphisms on W. Then there is an
action of End(W) on W∗ as follows: for a linear map S, and for w∗ in W∗ , v in W,
S ◦ w∗ (v) = w∗ (−Sv).
Under this action S infinitesimally preserves β :
β(S ◦ w∗ , v) + β(w∗ , Sv) = S ◦ w∗ (v) + w∗ (Sv)
= w∗ (−Sv) + w∗ (Sv) = 0.
Let V = W∗ + W. The pairing β can be extended to a symmetric, resp. skew-symmetric bilinear form
b on V by similar constructions as described above. Let I(V, b) denote the additive group of all linear
maps on V which infinitesimally preserve b. It turns out that it is the Lie algebra of the algebraic
group I(V, b).
Proposition 2.2. There is a canoninal embedding of End(W) into I(V, b).
Proof. Define the linear map hS : V → V as follows
(
S(v) if v ∈ W,
hS (v) =
S ◦ v if v ∈ W∗ .
EXISTANCE OF INVARIANT NON-DEGENERATE BILINEAR FORM UNDER A LINEAR MAP
7
Then hS preserves b infinitesimally : for w∗ ∈ W∗ , v ∈ W,
b(hS w∗ , v) + b(w∗ , hS v) = b(S ◦ w∗ , v) + b(w∗ , Sv)
= w∗ (−Sv) + w∗ (Sv) = 0.
Then S 7→ hS is the desired embedding.
2.2. The norm and the trace of a field extension. Let E be a finite extension of the field F of
degree [E : F]. We denote the field extension by E/F. For α in E, the map α̂ : E → E defined by
α̂(e) = αe is F-linear. The trace of α from E to F, denoted by T rE/F (α), is the trace of the F-linear
operator α̂. The norm of α from E to F, denoted by NE/F (α), is defined to be the determinant of α̂.
The trace is an F-linear map from E to E, i.e. for all e, e′ in E and a, b in F,
T rE/F (ae + be′ ) = aT rE/F (e) + bT rE/F (e′ ).
The norm is a multiplicative map, i.e. for all e, e′ in E, NE/F (ee′ ) = NE/F (e)NE/F (e′ ). Also for all a
in F, NE/F (ae) = a[E : F] NE/F (e). The trace form t on E is defined by t(e, e′ ) = T rE/F (ee′ ). The trace
form is non-degenerate if and only if the extension E/F is separable cf. Roman [8, Theorem-8.2.2,
p-204].
3. Invariant form under a linear map
3.1. Correspondence between symmetric and skew-symmetric forms. Let V be a vector space
over a field F. Suppose T in GL(V) is such that it has no eigenvalue 1 or −1. Let B be a T -invariant
non-degenerate symmetric bilinear form on V. Define a bilinear form B T on V as follows:
For u, v in V, B T (u, v) = B((T − T −1 )u, v).
Note that
B T (u, v) = B((T − T −1 )u, v)
= B(T u, v) − B(T −1 u, v)
= B(u, T −1 v) − B(u, T v), since T is an isometry
= B(u, T −1 v − T v)
= −B(u, (T − T −1 )v)
= −B((T − T −1 )v, u), since B is symmetric
= −B T (v, u).
Thus B T is a T -invariant non-degenerate skew-symmetric form on V. Also it follows by the same
construction that corresponding to each T -invariant skew-symmetric form, there is a canonical T invariant symmetric form. We summarize this discussion in a proposition.
Proposition 3.1. Let T be an element in GL(V). If T has no eigenvalue 1 or −1, then there exists
a T -invariant non-degenerate symmetric bilinear form on V if and only if there exists a T -invariant
non-degenerate skew-symmetric form on V.
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KRISHNENDU GONGOPADHYAY AND RAVI S. KULKARNI
3.2. Invariant form under a unipotent map.
Lemma 3.2. Let V be an n-dimensional vector space of dimension ≥ 2 over a field F of characteristic
different from 2. Let T : V → V be a unipotent linear map. Suppose V is equipped with a T -invariant
symmetric, resp. skew-symmetric bilinear form B. Let V be indecomposable with respect to T .
(i) Then B is either non-degenerate or B = 0.
(ii) Suppose B is non-degenerate. Then n must be odd, resp. even.
Proof. Let T be an unipotent linear map. Suppose the minimal polynomial of T is mT (x) = (x − 1)n .
Then without loss of generality we can assume that T is of the form
1 0 0 0 .... 0
1 1 0 0 .... 0
0 1 1 0 .... 0
(3.2.1)
T = .
.
..
..
.
0 0 0 0 .... 0
0 0 0 0 .... 1
Suppose T preserves a non-degenerate bilinear form B. In matrix form, let B = (aij ). Since T
preserves B, hence T t BT = B. This gives the following relations: For 1 ≤ i ≤ n − 1,
(3.2.2)
ai+1,n = 0 = an,i+1 ,
(3.2.3)
ai,j + ai,j+1 + ai+1,j + ai+1,j+1 = ai,j ,
(3.2.4)
i.e. ai,j+1 + ai+1,j + ai+1,j+1 = 0.
From the above two equations we have, for 0 ≤ l ≤ m − 1 and l + 1 ≤ i ≤ n − 1,
(3.2.5)
ai,n−l = 0 = an−l,i .
This implies that B is a triangular matrix of the form
a1,1
a1,2 a1,3 a1,4 .... a1,n−2 a1,n−1 a1,n
a2,1
a2,2 a2,3 a2,4 .... a2,n−2 a2,n−1
0
a3,1
a3,2 a3,3 a3,4 .... a3,n−2
0
0
(3.2.6)
B= .
,
..
..
..
..
..
..
..
.
.
.
....
.
.
.
0 ....
0
0
0
an−1,1 an−1,2 0
an,1
0
0
0 ....
0
0
0
where,
ai+1,j + ai,j+1 + ai+1,j+1 = 0.
Using (3.2.5) we have for 1 ≤ l ≤ n − 1,
(3.2.7)
al,n−l+1 = −al+1,n−l .
Using of the above equation with (3.2.4) yields, for 1 ≤ l ≤ n − 1,
(3.2.8)
al,n−l+1 = al,n−l + al+1,n−l−1
EXISTANCE OF INVARIANT NON-DEGENERATE BILINEAR FORM UNDER A LINEAR MAP
9
3.3. Proof of (i). Suppose B is degenerate. Hence the determinant of the matrix B must be zero.
Without loss of generality, in the form (3.2.6) of B we assume for 1 ≤ l ≤ n, al,n−l+1 = 0. Now, this
implies from (3.2.8), for 1 ≤ l ≤ n − 1, al,n−l = −al+1,n−l−1 . Thus for 1 ≤ l ≤ n − 1
(3.3.1)
al,n−l = (−1)n−2l an−l,l
Suppose B is symmetric, resp. skew symmetric. Then (3.3.1) implies that n must be even, resp. odd.
This is a contradiction to (i) above. Hence we must have for 1 ≤ l ≤ n − 1, al,n−l = 0. Continuing the
process, we have ai,j = 0 for all (i, j) 6= (1, 1). Choose a basis {e1 , ...., en } of V such that T and B has
the above forms with respect to the basis. Thus B(e1 , e1 ) = a1,1 , and T (e1 ) = e1 . The complementary
subspace of Fe1 is the radical of B and is T -invariant. This contradicts the assumption that V is
T -indecomposable. Hence we must have a1,1 = 0. Hence B = 0.
3.4. Proof of (ii). Suppose B is symmetric, resp. skew-symmetric and non-degenerate. From (3.2.7)
we have
al,n−l+1 = (−1)n+1−2l an−l+1,l .
Thus we must have n is odd, resp. even.
This completes the proof.
Lemma 3.3. Let V be an n-dimensional vector space of dimension ≥ 2 over a field F of characteristic
different from 2. Let T : V → V be a unipotent linear map. Let V be T -indecomposable. Then there
exists a T -invariant non-degenerate symmetric, resp. skew-symmetric bilinear form on V if and only
if n is odd, resp. even.
Proof. Without loss of generality, as in the proof of the previous theorem, assume T is of the
form (3.2.1). Then any bilinear form B of the form (3.2.6) is preserved by T . Consequently, as
in the above lemma, B is symmetric, resp. skew-symmetric, if and only if n is odd, resp. even.
Remark 3.4. In (3.2.1) if we replace 1 by a k × k identity matrix I, then the same procedure produces
a T -invariant non-degenerate symmetric, resp. skew-symmetric bilinear form according as nk is odd,
resp. even where n = dim V. In this case, in (3.2.6), each ai,j is replaced by a k × k matrix Ai,j and
they satisfy (3.2.4) i.e.
Ai+1,j + Ai,j+1 + Ai+1,j+1 = 0.
3.5. The Induced Form.
Lemma 3.5. Let V be a vector space over a field F of large characteristic. Let T : V → V be a
linear map with characteristic polynomial χT (x) = p(x)d , where p(x) is irreducible over F and is selfdual. Let V be indecomposable with respect to T . Then dim V is even, and there exists a T -invariant
non-degenerate symmetric, as well as skew-symmetric bilinear form on V.
Proof. Since V is T -indecomposable, (V, T ) is dynamically equivalent to the pair (F[x]/((p(x)d ), µx ),
where µx is the operator µ: [u(x)] 7→ [xu(x)], cf. Kulkarni [5]. Hence without loss of generality we
assume V = F[x]/((p(x)d ), T = µx .
Suppose that the degree of p(x) is 2m. Let y = x + x1 . Then x−m p(x) is a polynomial with
indeterminate y over F. We denote this polynomial in y by q(y). Since p(x) is irreducible, q(y) is also
irreducible. Since the characteristic of F is large, note that p′ (x) 6= 0.
10
KRISHNENDU GONGOPADHYAY AND RAVI S. KULKARNI
Let E = F[x]/(p(x)), and E1 = F[y]/(q(y)). Clearly E1 may be taken as a subfield of E. As a field
extension E has degree 2 over E1 . Since p′ (x) 6= 0, we see that each of the extensions E/F, E/E1 and
E1 /F, is separable. Note that NE/E1 defines a T -invariant E1 -valued quadratic form on E. We denote
the corresponding symmetric bilinear form by NE/E1 . Define B : E × E → F by
B(α, β) = T rE1 /F ((NE/E1 (α, 1)(NE/E1 (β, 1)).
Then B defines a non-degenerate T -invariant symmetric bilinear form on E. Correspondingly, there
exists a non-degenerate T -invariant skew-symmetric form σ on E. This proves the theorem for d = 1,
i.e. when T is semisimple.
Assume d is at least 2. It follows from Kulkarni [5] that there exists a basis such that
M O
I M
O I M
T =
,
I M
.
.
.. ..
I M
where M denote a 2m × 2m matrix with characteristic polynomial p(x) and I denote the 2m × 2m
identity matrix. All other entries in the above matrix are zeros. The matrix M is unique up to
conjugacy. Also, the Jordan-Wedderburn-Chevalley decomposition exists. Hence T = Ts Tu , where Ts
is semisimple, Tu is unipotent, Ts Tu = Tu Ts , and such a decomposition is unique. So, we can assume
Tu is of the form
(3.5.1)
I O
I I
O I
Tu =
..
.
O O
O O
O .... O
O .... O
O .... O
.
..
.
O O .... O
O O .... I
O
O
I
where each I is the 2m × 2m identity matrix, and n =
exists a non-degenerate symmetric, resp. skew-symmetric
is odd, resp. even. Further Bu is of the form
A1,1
A1,2 A1,3 A1,4 ....
A2,1
A2,2 A2,3 A2,4 ....
A3,1
A3,2 A3,3 A3,4 ....
(3.5.2)
Bu = .
..
..
..
..
.
.
.
....
O ....
Ad−1,1 Ad−1,2 O
Ad,1
O
O
O ....
where each Ai,j is a 2m × 2m matrix and
(3.5.3)
2md. As mentioned in Remark 3.4, there
dim V
bilinear form Bu according to d = deg
p(x)
A1,d−2 A1,d−1 A1,d
A2,d−2 A2,d−1 O
A3,d−2
O
O
,
..
..
..
.
.
.
O
O
O
O
O
O
Ai+1,j + Ai,j+1 + Ai+1,j+1 = 0.
EXISTANCE OF INVARIANT NON-DEGENERATE BILINEAR FORM UNDER A LINEAR MAP
11
As we have seen in the previous section, Bu can be made symmetric, resp. skew-symmetric if and
only if d is odd, resp. even.
In the Jordan decomposition, let
(3.5.4)
M
O
Ts =
O
O
O
M
...
...
..
.
O
O
O
O
...
...
M
O
O
O
,
O
M
where M is a semisimple matrix with characteristic polynomial p(x). By the semisimple case above,
there exists a M -invariant non-degenerate symmetric, as well as a skew-symmetric bilinear form. Let
b be a non-degenerate M -invariant symmetric bilinear form. Then in matrix representation b is a
2m × 2m symmetric non-singular matrix.
Case (i): Suppose d is odd. Let d = 2k + 1. We want to construct Bu so that it is non-degenerate,
symmetric and is invariant under Ts .
Assume, for all i, j, Ai,j = Aj,i . Consider an element αk,l in Ai,j . Then αk,l is the (2m(i − 1) +
k, 2m(j − 1 + l)-th entry of Bu . Then αl,k in Aj,i is the (2m(j − 1) + 1, 2m(i − 1) + k)-th entry of Bu .
If αl,k = αk,l , i.e. if Ai,j is chosen to be symmetric, then Bu is symmetric. Thus, for all i, j, if we
choose Ai,j to be symmetric, then Bu would be symmetric.
For 1 ≤ l ≤ d − 1, choose Al,d−l+1 = (−1)l−1 b. Note that Ad−l+1,l = (−1)d−l b = (−1)2k−(l−1) b =
(−1)l−1 b = Al,d−l+1 . Hence the choice satisfies the assumed symmetricity of Bu .
Using the above choice, we have from (3.5.3) the following set of equations:
(3.5.5)
A1,d−1 + A2,d−2 = b
(3.5.6)
A2,d−2 + A3,d−3 = −b
..
.
(3.5.7)
(3.5.9)
Al,d−l + Al+1,d−l−1 = (−1)l+1 b
..
.
(3.5.10)
Ak−1,k+2 + Ak,k+1 = (−1)k b
(3.5.11)
Ak,k+1 + Ak+1,k = (−1)k+1 b.
(3.5.8)
By the assumption that Bu is symmetric, we rewrite the last equation as 2Ak,k+1 = (−1)k+1 b,
i.e. Ak,k+1 = (−1)k+1 2b . Now by back-substitution we have, for 1 ≤ m ≤ k − 1, Ak−m,k+m+1 =
12
KRISHNENDU GONGOPADHYAY AND RAVI S. KULKARNI
(−1)k−m+1
2m+1
2 b.
Next we have the following set of equations:
2k − 3
b
2
2k − 5
b
=−
2
(3.5.12)
A1,d−2 + A2,d−3 =
(3.5.13)
A2,d−3 + A3,d−4
(3.5.14)
..
.
(3.5.15)
Ak−l+1,k+l+1 + Ak−l+1,k+l = (−1)k−l+2
(3.5.16)
..
.
(3.5.17)
3
Ak+1,k−1 + Ak+2,k = −Ak+2,k−1 = (−1)k b.
2
2l + 1
b
2
We already have the initial value Ak,k+2 = Ak+2,k = (−1)k−1 b. From the last equation we have
Ak+1,k−1 = Ak−1,k+1 = (−1)k 25 b. Now by back substitution as in the previous case, we get other
solutions. Continuing the process, we have for all i, j, (i, j) 6= (1, 1), Ai,j as a multiple of b by a
rational number over F. Put A1,1 = b. Then Bu is symmetric and non-degenerate. Now, each of the
2m × 2m block of Bu is invariant under M . Hence Ts Bu Tst = Bu . Thus Bu is invariant under Ts ,
as well as it is invariant under Tu . Hence Bu is a non-degenerate symmetric bilinear form invariant
under T .
Thus when d is odd, T has a invariant non-degenerate symmetric bilinear form. Consequently by
Proposition 3.1, there exists a non-degenerate invariant skew-symmetric bilinear form.
Case (ii): Suppose d is even, let d = 2k. In this case Bu can not be symmetric. We wish to construct
a non-degenerate skew-symmetric bilinear form Bu which is invariant under both Ts and Tu .
Assume for all i, Ai,i = O, and for all i, j, Ai,j = −Aj,i . As in the above case, we see that for
all i, j, if Ai,j is chosen to be symmetric, then Bu would be skew-symmetric. Hence we choose for
1 ≤ l ≤ k, Al,n−l+1 = (−1)l−1 b. Now using (3.5.3) and following similar procedure as above, we obtain
a skew-symmetric non-degenerate bilinear form Bu which is invariant under both Tu and Ts , and hence
it is also T -invariant. Consequently, by Proposition 3.1, there also exists a T -invariant non-degenerate
symmetric bilinear form.
This completes the proof.
The following proposition follows immediately from the above lemma.
Proposition 3.6. Let V be a vector space over a field F of large characteristic. Let T : V → V be a
linear map with characteristic polynomial χT (x) = Πki=1 pi (x)di , where for each i = 1, 2, ..., k, pi (x) is
self-dual and is irreducible over F. Then there exists a non-degenerate T -invariant symmetric, as well
skew-symmetric bilinear form on V.
3.6. Proof of Theorem 1.3. For a unipotent isometry T : V → V with minimal polynomial (x − 1)k ,
we observe that −T : V → V is also an isometry with minimal polynomial (x+1)k , and also the converse
holds. Hence it is enough to prove the theorem for unipotents.
Let B be symmetric. Let T : V → V be a unipotent isometry in I(V, B). Let W be a T indecomposable and orthogonally indecomposable subspace of V. Since B|W is non-degenerate, we see
that dim W must be odd by Lemma 3.3.
EXISTANCE OF INVARIANT NON-DEGENERATE BILINEAR FORM UNDER A LINEAR MAP
13
Suppose dim W is even. Then B|W = 0 by Lemma 3.2. Since B is non-degenerate, there is a
T -invariant T -indecomposable subspace W′ such that B|W′ = 0, dim W = dim W′ and W + W′ is nondegenerate. Hence the multiplicity of the elementary divisor (x − 1)k must be even. This completes
the proof of Theorem 1.3.
3.7. Proof of Theorem 1.4. The proof is similar as above.
4. Proofs of Theorem 1.1 and Theorem 1.2
Lemma 4.1. Suppose T admits an invariant non-degenerate symmetric (resp. skew-symmetric) bilinear form B. Suppose T has no eigenvalue 1 or −1. Then the minimal polynomial mT (x) of T is
self-dual.
Proof. Note that for u, v in V we have B(T u, v) = B(u, T −1 v). Using this identity it follows that for
any f (x) in F[x], B(f (T )v, w) = B(v, f (T −1 )w). Applying this to the minimal polynomial of T we
have for all v in V, mT (T −1 )v = 0. Thus if λ in F̄ is a root of the minimal polynomial, then λ−1 is
also a root. Thus the minimal polynomial of T is self-dual.
Let p(x) be an irreducible factor of the minimal polynomial of To . Lemma 4.1 implies that p(x)
is either self-dual, or there is an irreducible factor p∗ (x) such that p(x) is dual to p∗ (x). Suppose
p(x) 6= p∗ (x). Let Vp = ker p(T )n , Vp∗ = ker p∗ (T )n , where n = dim V. Then B|Vp = 0 = B|Vp∗
and B|Vp +Vp∗ is non-degenerate.
4.1. Proofs of Theorem 1.1 and Theorem 1.2. Suppose T admits an invariant non-degenerate
symmetric (resp. skew-symmetric) bilinear form B. Let ⊕ denote the orthogonal sum and + denote
the usual sum of subspaces. It can be seen easily that there is a primary decomposition of V (with
respect to T ) into T -invariant non-degenerate subspaces:
M
1
2
(4.1.1)
V = ⊕ki=1
⊕kj=1
Vi
Vj
where for i = 1, 2, ..., k1 , pi (x) is self-dual, Vi = Vpi , and B|Vi is non-degenerate; for j = 1, 2, ..., k2 ,
Vj = Vpj + Vp∗j , B|Vpj = 0 = B|Vp∗ , here pj (x) 6= p∗j (x).
j
So, without loss of generality assume V is of the form Vi or Vj , i.e. mTo (x) is of either of the form
p(x)d or q(x)d q ∗ (x)d , where p(x), q(x), q ∗ (x) are irreducible over F, and q ∗ (x) is dual to q(x).
Case (i). Suppose mTo (x) = p(x)d , where p(x) is self-dual and irreducible over F. By the theory
of Jordan-canonical form, we have a direct sum decomposition: V = Σki=1 Vdi , where 1 ≤ d1 < .... <
dk = d, and for each i = 1, ..., k, p(x)di is an elementary divisor, Vdi is T -invariant and is free over the
algebra F[x]/(p(x)di ). We claim that each Vdi is non-degenerate. For this it is sufficient to show that
Vd is non-degenerate. The non-degeneracy of the other summands will follow by induction.
If possible, suppose Vd is degenerate. Let R(Vd ) be the radical of Vd , that is,
R(Vd ) = {v ∈ Vd | B(v, Vd ) = 0}.
Let v be a non-zero element in R(Vd ). Since R(Vd ) is T -invariant, let p(T )v = 0. By the theory of
elementary divisors it follows that there exist a u in Vd such that p(T )d−1 u = v. Then for all i < d,
and w in Vdi ,
B(p(T )d−1 u, w) = B(u, p(T −1 )d−1 w) = 0.
14
KRISHNENDU GONGOPADHYAY AND RAVI S. KULKARNI
Hence v is orthogonal to V, a contradiction to the non-degeneracy of B. Thus Vd must be nondegenerate. Thus for each i, Vdi is non-degenerate. Note that the minimal polynomial of T |Vdi is
p(x)di . Hence p(x)di is self-dual.
Case (ii). mTo (x) = p(x)d p∗ (x)d , where p(x), p∗ (x) are irreducible over F, p(x) 6= p∗ (x) and
V = Vp + Vp∗ , dim Vp = dim Vp∗ , B|Vp = 0 = B|Vp∗ . By the theory of Jordan Canonical form, V has
a direct sum decomposition: V = Σki=1 Vpdi + Σlj=1 Vp∗ cj ), where for each 1 ≤ d1 < d2 < ... < dk = d,
1 ≤ c1 < c2 < ... < cl = d, Vpdi , resp. Vpci ∗ , is T -invariant and is free over the algebra F[x]/(p(x)di ),
resp. F[x]/(p∗ (x)ci ). We claim that k = l and for each i, ci = di . Using arguments similar as above,
it is easy to see that B is non-degenerate on Vpd + Vp∗d . Now by induction the claim follows. Since
the minimal polynomial of T |V di +V ∗ di is p(x)di p∗di . Hence for each elementary divisor p(x)di there
p
p
is a dual elementary divisor p∗ (x)di with the same multiplicity.
Suppose (x − 1)k , resp. (x + 1)k , is an elementary divisor of T . Let W be a T -indecomposable
subspace of V such that T |W has characteristic polynomial (x − 1)k , resp. (x + 1)k . Suppose B
is symmetric (resp. skew-symmetric). Then it follows from Lemma 3.3 that B|W is either zero or
non-degenerate. From Theorem 1.3 we have that B|W is nondegenerate if and only if k is odd (resp.
even). If B|W = 0, then k must be even (resp. odd). Thus if k is even (resp. odd), then by the
non-degeneracy of B it follows that W is a summand of a standard symmetric (resp. skew-symmetric)
space, and hence the multiplicity of (x − 1)k must be even (resp. odd).
Conversely, suppose (i) and (ii) of either of the theorems hold. For an elementary divisor g(x), let
Vg denote the T -indecomposable subspace isomorphic to F[x]/(g(x)). From the theory of elementary
divisors it follows that V has a decomposition
(4.1.2)
m2
1
∗
V = Σm
i=1 Vfi + Σj=1 (Vgi + Vgi ),
where for each i = 1, 2, ..., m1 , fi (x) is either self-dual, or one of (x + 1)k and (x − 1)k , for each
j = 1, 2, ..., m2 , gi (x), gi∗ (x) are dual to each other and gi (x) 6= gi∗ (x). To prove the theorem it is
sufficient to induce a T -invariant quadratic (resp. skew-symmetric) form on each of the summands.
Suppose W is an indecomposable summand in the above decomposition and p(x)k be the corresponding elementary divisor.
(a) Suppose p(x)k is self-dual. It follows from Proposition 3.6 that there exists a T -invariant nondegenerate symmetric, as well as skew-symmetric bilinear form on W.
Suppose p(x)k is not self-dual. Then there is a dual elementary divisor p∗ (x)k . As explained in
section 2.1, there exists a T -invariant standard form on Wp + Wp∗ , where Wp = ker p(T )k , Wp∗ =
ker p∗ (T )k .
(c) Suppose, p(x)k = (x − 1)k . Suppose k is odd (resp. even). Then the respective symmetric and
skew-symmetric bilinear form is obtained from Lemma 3.2 and Lemma 3.3.
Let k = 2m, resp. 2m + 1, and the multiplicity of (x − 1)2m is an even number. Then the number
of indecomposable summands, each isomorphic to F[x]/(x − 1)k , in the decomposition (4.1.2) is even.
We can pair those summands, taking two at a time, and induce a T -invariant standard form on each
pair.
(d) Suppose p(x)k = (x+1)k . Let Tw denote the restriction of T to W. Then the minimal polynomial
of Tw is (x + 1)k . Thus the minimal polynomial of −Tw is (x − 1)k . Further Tw preserves a symmetric
(resp. skew-symmetric) form B if and only if −Tw also preserves B. Thus this case reduces to the case
EXISTANCE OF INVARIANT NON-DEGENERATE BILINEAR FORM UNDER A LINEAR MAP
15
(c) above, and there exists a T -invariant non-degenerate symmetric (resp. skew-symmetric) bilinear
form on W.
This completes the proofs of Theorem 1.1 and Theorem 1.2.
4.2. Proof of Corollary 1. The proof follows from the fact that χT (x) is self-dual, hence V has
the decomposition (4.1.2). Now on each of the T -invariant component one can induce a T -invariant
non-degenerate symmetric or skew-symmetric form according to Theorem 1.1 and Theorem 1.2. This
completes the proof.
5. Proofs of Theorem 1.6 and Theorem 1.7
Suppose T : V → V is unipotent. Let W be a T -indecomposable subspace of V of maximal
dimension, i.e. W is isomorphic to F[x]/(x − 1)k . If B|W = 0, then k ≤ l. If k > l, then B|W is
non-degenerate and hence k must be odd by Lemma 3.2.
Suppose k > l. Let k = 2m + 1 ≥ 3. Let W1 = ker(T |W − I). Since W is T -indecomposable, we
must have B|W1 = 0. Hence r = dim W1 can be at most l. Now observe that the non-degeneracy
of W implies that k is at least 2r + 1. By the indecomposibility of W, k = 2r + 1. Assume W1 has
the maximal dimension. Hence if the dimension of V is 2l, then r = l − 1 and k ≤ 2l − 1. Suppose
dim V ≥ 2l + 1. Then r = l and dim W = 2l + 1.
This completes the proof of Theorem 1.6.
The proof of Theorem 1.7 is similar.
6. The infinitesimal version: Proofs of Theorem 1.8 and Theorem 1.9
We note the infinitesimal versions of the key lemmas which are crucial to the proof. First we note
the infinitesimal versions of Lemma 3.2 and Lemma 3.3.
Lemma 6.1. Let V be a vector space over a field F of large characteristic. Let V be equipped with
a symmetric, resp. skew-symmetric, bilinear form B. Suppose T : V → V be a nilpotent map which
keeps B infinitesimally invariant. Let W be a T -indecomposable subspace of V.
(i) Then B|W is either non-degenerate or B|W = 0.
(ii) If B|W is non-degenerate, then the dimension of W must be odd, resp. even.
Lemma 6.2. Let V be a vector space of dimension n ≥ 2 over a field F of large characteristic. Let
T : V → V be a nilpotent linear map. Let V be T -indecomposable. Then there exists an infinitesimally
T -invariant non-degenerate symmetric, resp. skew-symmetric bilinear form on V if and only if n is
odd, resp. even.
Next we have the following infinitesimal version of Proposition 3.1.
Proposition 6.3. Let T be a linear map. If T has no eigenvalue 0, then there exists an infinitesimally
T -invariant non-degenerate symmetric bilinear form on V if and only if there exists an infinitesimally
T -invariant non-degenerate skew-symmetric bilinear form on V.
Proof. Suppose B is an infinitesimally T -invariant non-degenerate symmetric bilinear form:
for x y in V,
(6.0.1)
B(T x, y) + B(x, T y) = 0.
16
KRISHNENDU GONGOPADHYAY AND RAVI S. KULKARNI
For x, y in V, define B T (x, y) = B(T x, y). Then B T is a non-degenerate skew-symmetric bilinear
form and it is also infinitesimally T -invariant:
B T (T x, y) + B T (x, T y) = B(T 2 x, y) + B(T x, T y)
= −B(T x, T y) + B(T x, T y), by (6.0.1), B(T (T x), y) = −B(T x, T y)
= 0.
The converse part follows by reversing the steps.
Lemma 6.4. Let V be a vector space over a field F of large characteristic. Let S : V → V be a linear
map with characteristic polynomial χS (x) = p(x)d , where p(x) is irreducible over F and is even. Let V
be S-indecomposable. Then dim V is even, and there exists a infinitesimaly S-invariant non-degenerate
symmetric, as well as skew-symmetric bilinear form on V.
Proof. Without loss of generality assume that V = F[x]/((p(x)d ). Let y = x2 . Replacing y by x2
√
in p(x), we see p( y) is a polynomial in indeterminate y over F, and we denote it by q(y). Let
E = F[x]/(p(x)), and E1 = F[y]/(q(y)). Clearly E1 may be taken as a subfield of E, and as a field
extension E has degree 2 over E1 . Since p′ (x) 6= 0, E1 /F, and E/E1 are separable extensions. Note
that [E : E1 ] = 2, hence NE/E1 defines an E1 -valued non-degenerate symmetric bilinear form NE/E1 on
E:
for α, β ∈ E1 ,
1
NE/E1 (α, β) = [NE/E1 (α + β) − NE/E1 (α) − NE/E1 (β)].
2
It is easy to check that it is infinitesimally S-invariant. Now, define B : E × E → F as follows.
For α, β ∈ E, B(α, β) = T rE1 /F (NE/E1 (α, 1)NE/E1 (β, 1)).
Then B is a non-degenerate, symmetric and infinitesimally S-invariant. Correspondingly, by Proposition 6.3, there exists an infinitesimally S-invariant non-degenerate skew-symmetric bilinear form.
This proves the theorem for d = 1.
Suppose d is at least 2. It follows from Kulkarni [5] that there exists a basis such that S = Ss + Sn ,
where Ss is semisimple, Sn is nilpotent, Ss Sn = Sn Ss and the decomposition is unique. Now the proof
is similar to that of Lemma 3.5.
The rest of the proofs of the infinitesimal versions are similar to those of Theorem 1.1 and Theorem 1.2. We omit the details.
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Indian Institute of Science Education and Research (IISER) Mohali, Transit Campus: MGSIPAP Complex, Sector-26, Chandigarh 160019, India
E-mail address: krishnendu@iisermohali.ac.in, krishnendug@gmail.com
Department of Mathematics, Indian Institute of Technology Bombay, Powai, Mumbai 400076, India
E-mail address: punekulk@gmail.com